Answer:
D. 54,900
Step-by-step explanation:
We have been given that the salary of teachers in a particular school district is normally distributed with a mean of $50,000 and a standard deviation of $2,500.
To solve our given problem, we need to find the sample score using z-score formula and normal distribution table.
First of all, we will find z-score corresponding to probability
using normal distribution table.
From normal distribution table, we get z-score corresponding is
.
Now, we will use z-score formula to find sample score as:
, where,
= Z-score,
= Sample score,
= Mean,
= Standard deviation





Therefore, the salary of $54900 divides the teachers into one group that gets a raise and one that doesn't.
Answer:
x<7
Step-by-step explanation:
hope this helps :)
Answer:
D. The company's chocolate bars weigh 3.2 ounces on average.
Step-by-step explanation:
We are given that a company claims that its chocolate bars weigh 3.2 ounces on average.
The company took many large samples, and each time the mean weight of the sample was within the 95% confidence interval.
Definition of 95% confidence level: 95% confidence level means a range of values that you can be 95% certain contains the true mean of the population.
Thus by considering definition we can conclude that The company's chocolate bars weigh 3.2 ounces on average.
Thus Option D is correct.
D. The company's chocolate bars weigh 3.2 ounces on average.
2x²-3xy-2y²-2x-11y-12
Write -3xy as a difference
2x²+xy-4xy-2y²-2x-11y-12
write -2x as a difference
2x²+xy-4xy-2y²+4x-6x-11y-12
Write -11y as a difference
2x²+xy-4xy-2y²+4x-6x-8y-3y-12
Factor out 2x from the expression
2x×(x-2y-3)+xy-2y²+4x-8y-3y-12
Factor out y from the expression
2x×(x-2y-3)+y×(x-2y-3)+4x-8y-12
Factor out 4 from the expression
2x×(x-2y-3)+y×(x-2y-3)+4(x-2y-3)
Factor out x-2y-3 from the expression
Answer: (x-2y-3)x(2x+y+4)
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Answer:
✓73 or approximately 8.54
Step-by-step explanation:
✓ 8²+3² = ✓ 73 or approximately 8.54