Two factors that give a product of 1600 can be 80 × 20
The product of multiple perfect cubes is also a perfect cube.
Proof for two:
n^3 * p^3 = nnnppp = npnpnp = (np)^3
And any integer whose exponent is a multiple of 3 is a perfect cube.
We will use this here:
Prime factorize 3240:
3240 = 405 * 2^3 = 2^3 * 3^4 * 5^1
We need to multiply this by k, to make all the exponents divisible by 3
The exponents not divisible by 3 are 4 and 1.
So let's fix that:
2^3 * 3^4 * 3*2 * 5^1 * 5^2
So, k is 3^2 * 5^2 = 225
(3240*225)^(1/3) = 90
Answer:
Step-by-step explanation:
Ok, if you say so. Jean took 1/2 hour to complete 3/8 of a math problem.
Answer:
The correct answer is x = 17.
Step-by-step explanation:
If EF bisects DEG, this means that angles DEF and angles FEG are congruent, and they each make up half of angle DEG.
Therefore, we can set up the equation:
DEF + FEG = DEG
However, since we know that DEF and FEG represent the same value, we can change this equation into the following:
2(DEF) = DEG
Now, we can substitute in the expressions that we are given:
2(3x+1) = 5x + 19
To simplify, we should first use the distributive property on the left side of the equation.
6x + 2 = 5x + 19
Our next step is to subtract 5x from both sides of the equation.
x + 2 = 19
Finally, we can subtract 2 from both sides of the equation to get x by itself on the left side.
x = 17
Therefore, the value of x is 17.
Hope this helps!
