<h3>Given Equation:</h3>
x = 7 + 3y
or, x - 3y - 7 = 0 ........ (i)
5x + 6y = 14
or, 5x + 6y - 14 = 0 .........(ii)
<h3>To Find:</h3>
The value of x and y.
<h3>Solution:</h3>
By dividing eq. ii by 2, we get
5/2x + 3y - 7 = 0 ........ (iii)
By adding eq. i and eq. iii, we get
15/2x = 0
or, <u>x = 0</u> ........(iv)
By putting eq.(iv) in eq. (i), we get
0 - 3y - 7 = 0
or, -3y = 7
or, <u>y = </u><u>-</u><u>7/</u><u>3</u>
<h2>Answer: ( 0, -7/3 )</h2>
The value of x and y is 0 and -7/3 respectively.
(b^4)^3
To simplify when something is raised to two different exponents, multiply the two exponents together:
4 * 3 = 12
You now have b^12.
The answer is D.
Answer:
Step-by-step explanation:
If ΔABC ~ ΔDEF
Then their sides must be proportional such that:
=> 
Cross Multiplying
=> x * 6 = 8*3
=> 6x = 24
Dividing both sides by 6
=> x = 4
Answer:
Nitrogen has an atomic number of 7 (Z=7) because it has 7 protons in its nucleus.
I think that's what you're looking for
?? I can always be wrong.
Good luck, hope this helped!
<em>Greetings from Brasil...</em>
With the recursive formula, lets build the sequence:
A1 = 4
A2 = A1 - 7
A3 = A2 - 7
A4 = A3 - 7
A5 = A4 - 7
(...)
But pay attention to A3....
A3 = A2 - 7 but A2 = A1 - 7 , so rewriting A3
A3 = (A1 - 7) - 7 ⇒ A3 = A1 + 2.(- 7)
A4 = A3 - 7 ⇒ A4 = [(A1 - 7) - 7] - 7 = A1 + 3.(- 7)
A5 = {[(A1 - 7) - 7] - 7} - 7 = A5 + 4.(- 7)
so
<h3>An = A1 + (n - 1).(- 7)</h3>
