If anything is in parentheses do that first, however if there isn’t you always do exponents next so evaluate 6 squared
Hope this helps!!
Answer:
183 miles to the nearest mile.
Step-by-step explanation:
Distance =Speed X Time
Distance of Truck B from point A=45 X2 =90 miles
Distance of Truck C from point A=55 X2 =110 miles
Angles between them, BAC=132°
We want to find the Distance BC denoted by a between the trucks.
Using Cosine Rule,
a²=b²+c²-2bcCos A
=90²+110²-(2X90X110XCos132°)
=33448.79
a=√33448.79
BC=182.89 miles
The distance between the trucks is 183 miles to the nearest mile.
Answer:
at 6pm it was 18 degrees
Step-by-step explanation:
10 pm: -10
9 pm : -3
8 pm: 4
7 pm: 11
6 pm: 18
Add 7
Answer:
g^5h^2
Step-by-step explanation:
12g^5h^4, g^5h^2
This is one way of doing it. Break down every number and every variable into a product of the simplest factors. Then see how many of each factor appear in both monomials.
12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h
g^5h^2 = g * g * g * g * g * h * h
So far you see every single prime factor of each monomial.
Now I will mark the ones that are present in both. Those are the common factors.
12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h
g^5h^2 = g * g * g * g * g * h * h
The greatest common factor is the product of all the factors that appear in both monomials.
GCF = g * g * g * g * g * h * h = g^5h^2
There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.

The probability is 1/57.