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3 years ago

11. Anna's goal is to walk 12 miles a week. This week, she walked 1 and 2/3

Mathematics

1 answer:

elena-s [515]3 years ago

7 0

Answer:

2 Miles

Step-by-step explanation:

1 2/3 x 6 = 10

( She needs to walk 2 more miles )

Tomorrow Anna should run 2 miles to reach her goal.

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Please help me withe this proof as well.

baherus [9]

- D is the midpoint of AB, E is the midpoint of BC

Answer: A. Given

I left off DB||FC because that's not given. But we can construct it.

Construct line through C parallel to AB. Extend DE to intersect and call the meet F.

- DB || FC

By Construction

----

- Angle B congruent to angle FCE

Answer: D. Alternate Interior Angles

We have transversal BC across parallel lines AB and CF, so we get congruent angles ABC and FCB aka FCE

- angle BED congruent to angle CEF

Answer: H. Vertical angles are congruent

When we get lines meeting like this we get the usual congruent and supplementary angles.

- Triangle BED congruent to Triangle CEF

Answer: F. Angle Side Angle

We have BE=CE, DBE=FCE, BED=CEF

- DE congruent to FE and DB congruent to FC

Answer: C. CPTCTF

Corresponding parts ...

- AD congruent to DB and DB congruent to FC therefore AD congruent to FC

Answer: E. Transitive Property of Congruent

Things congruent to the same thing are congruent

- ADFC is a parallelogram

Answer: G. AD and FC are congruent and parallel

Presumably this is a theorem we have already established.

- DE || AD

Answer: B. Definition of a parallelogram

4 0

3 years ago

The length and width of a rectangle are consecutive integers. The perimeter of the

Hunter-Best [27]

The length of the rectangle is 9 feet and the width of the rectangle is 10 feet.

<h3>What is the Perimeter of a Rectangle?</h3>

The sum of a rectangle's boundary lengths on all sides is known as its perimeter. A rectangle's perimeter is a linear measurement that can be expressed in meters, feet, inches, or yards. Let's first comprehend the two fundamental characteristics of a rectangle.

A rectangle has four 90° angles.
The lengths of a rectangle's diagonals are equal.

Let the length of the rectangle be x feet

Then, the width of the rectangle will be x+1feet

We know that the perimeter of a rectangle is given by

P= 2(l+w)

Here

P= perimeter of a rectangle

l=length of the rectangle

w= width of the rectangle

Put l=x, w= x+1 and P= 38 in the perimeter formula

38 = 2(x+x+1)

Divide both sides by 2

19= x+x+1

19= 2x+1

Subtract 1 from both sides

18=2x

Divide both sides by 2

x=9 feet

This is the length of the rectangle.

Now, the width x+1 of the rectangle will be

9+1 = 10 feet

To know more about the perimeter of a rectangle, visit:

brainly.com/question/2142493

#SPJ9

5 0

1 year ago

Based on recent records, the manager of a car painting center has determined the following probability distribution for the numb

posledela

So the answer is going to 6746

8 0

3 years ago

the number of points in the first five games of the football season are listed below. what is the mean number of points scored?

yarga [219]

^ You again? Quit being sus and answer the question here instead of elsewhere.

To find the mean, all you have to do is add each number and then divide by how many numbers you added.

So, 38 + 29 + 16 + 42 + 33 = 158. There were five numbers added, so the next step is to divide 158 by 5. That equals 31.6 as your answer.

3 0

3 years ago

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

Oksana_A [137]

Answer:

$n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}$

Step-by-step explanation:

Lets divide it in cases, then sum everything

Case (1): All 5 numbers are different

In this case, the problem is reduced to count the number of subsets of cardinality 5 from a set of cardinality n. The order doesnt matter because once we have two different sets, we can order them descendently, and we obtain two different 5-tuples in decreasing order.

The total cardinality of this case therefore is the Combinatorial number of n with 5, in other words, the total amount of possibilities to pick 5 elements from a set of n.

${n \choose 5 } = \frac{n!}{5!(n-5)!}$

Case (2): 4 numbers are different

We start this case similarly to the previous one, we count how many subsets of 4 elements we can form from a set of n elements. The answer is the combinatorial number of n with 4 ${n \choose 4} .$

We still have to localize the other element, that forcibly, is one of the four chosen. Therefore, the total amount of possibilities for this case is multiplied by those 4 options.

The total cardinality of this case is $4 * {n \choose 4} .$

Case (3): 3 numbers are different

As we did before, we pick 3 elements from a set of n. The amount of possibilities is ${n \choose 3} .$

Then, we need to define the other 2 numbers. They can be the same number, in which case we have 3 possibilities, or they can be 2 different ones, in which case we have ${3 \choose 2 } = 3$ possibilities. Therefore, we have a total of 6 possibilities to define the other 2 numbers. That multiplies by 6 the total of cases for this part, giving a total of $6 * {n \choose 3}$

Case (4): 2 numbers are different

We pick 2 numbers from a set of n, with a total of ${n \choose 2}$ possibilities. We have 4 options to define the other 3 numbers, they can all three of them be equal to the biggest number, there can be 2 equal to the biggest number and 1 to the smallest one, there can be 1 equal to the biggest number and 2 to the smallest one, and they can all three of them be equal to the smallest number.

The total amount of possibilities for this case is

$4 * {n \choose 2}$

Case (5): All numbers are the same

This is easy, he have as many possibilities as numbers the set has. In other words, n

Conclussion

By summing over all 5 cases, the total amount of possibilities to form 5-tuples of integers from 1 through n is

$n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}$

I hope that works for you!

4 0

3 years ago