The mean absolute deviation for the number of hours students practiced the violin is 6.4.
<h3>What is the mean absolute deviation?</h3>
The average absolute deviation of the collected data set is the average of absolute deviations from a center point of the data set.
Given
Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours.
The given data set is;
45, 38, 52, 58, 42
Mean Deviation = Σ|x − μ|/N.
μ = mean, and N = total number of values
|x − μ| = |45 − 47| = 2
|38− 47| = 9
|52− 47| = 5
|58− 47| = 11
|42− 47| = 5
The mean absolute deviation for the number of hours students practiced the violin is;

Hence, the mean absolute deviation for the number of hours students practiced the violin is 6.4.
To know more about mean value click the link given below.
brainly.com/question/5003198
For a 19 foot scale find the frequency of a note to the frequency of the preceding note?
Answer:
5/8.
Step-by-step explanation:
3/4 equals 6/8 and 6/8 minus 1/8 (being subtracted) is 1/8.
I did not use Siri
Answer:
I just need 5 points for brainly please give me 5 stars
Step-by-step explanation: