Using properties to find the sum and product of 5 times 23 times 2

Mathematics

1 answer:

Nonamiya [84]3 years ago

7 0

The Answer is 230 23*5 is 115*2 is 230

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What is 5 3/8 as a inproper fracon and as a mixed number

ICE Princess25 [194]

$\frac{53}{8}$
To divide 53 by 8 wont be possible so u find a number that when you multiply by 8 it gives u a number closer to 58 which is 8*6=48 i.e 53 divided by 8 is 6 rem, then to get the reminder you subtract 42 from 53 i.e 53–48=5 so the final answer will be 6 and 5/6

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3 years ago

5 1/2 x 3 3/4 please help

Svetach [21]

Answer:

5 1/2 is also known as 11/2 and 3 3/4 is also know as 15/4. Now times 11/2 x 15/4. 165/8 is the answer i think

Step-by-step explanation:

you make everything an improper fraction then times it

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2 years ago

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$