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Alja [10]
3 years ago
5

Write an inequality for the following problem. Use X as your variable. 10 less than 7 times a number is greater then 56.

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

7x -10 > 56

Step-by-step explanation:

For this you simply write what the sentence states. Ten less means you are subtracting 10 from 7 times a number, x. So, 7x -10. The statement also says this is greater than 56, so put >56, for 7x-10>56.

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Un productor agricola tiene que envasar huevos en cajas de 12, de 6 o de 30. Si sabemos que tiene un numero parecido a 1000 huev
musickatia [10]

Answer:

El productor tiene que envasar 960 huevos.

Step-by-step explanation:

Es necesario determinar el mínimo común múltiplo de 6, 12 y 30. En primer lugar, se determina cada número como productos de números primos:

6 = 2\times 3

12 = 2^{2}\times 3

30 = 2\times 3\times 5

El mínimo común múltiplo es:

M.C.M. = 2^{2}\times 3\times 5

M.C.M. = 60

El número total de huevos próximo a 1000 unidades es un múltiplo del mínimo común múltiplo:

n = 60\times 16

n = 960

El productor tiene que envasar 960 huevos.

5 0
3 years ago
What is the answer ?
Anuta_ua [19.1K]

Answer:

x= y+2/3+4

Step-by-step explanation:

5 0
3 years ago
Find the value of x and y. y=2x and 1.85x+3.7y=12.95
Len [333]

Answer:

x=1.4 y=2.8

Step-by-step explanation:

Lets substitute y with 2x. We get: 1.85x+7.4x=12.95.

Simplifying by combining x: 9.25x=12.95

Then you just divide 12.95 by 9.25: x=1.4

Now for y. We know why is 2x so we just have to multiply x by 2: y=2x, y=2.8.

3 0
3 years ago
Show 1,700 using large cubes and flats
IgorC [24]

Answer:

How will the size of the model for 100,000 compare to the size of the model for 10,000? Possible answer: the pattern shows cube, long, flat, cube. So, the shape of the model for 10,000 will be long.

Step-by-step explanation:

3 0
4 years ago
Please help me with this. I forgot the formula for this
Lapatulllka [165]
There is the formula now just plug in the values and you will get your answer.

7 0
4 years ago
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