Answer:
attempts are required to find a matching pair if the digital fingerprint is 64 bits long.
attempts are required to find a matching pair if the digital fingerprint is 128 bits long.
Step-by-step explanation:
Each bit has two options. So
How many attempts are required to find a matching pair if the digital fingerprint is 64 bits long?
So for each of the 64 bits, we have the following number of options.
2 - 2 - 2 - 2 -... - 2
So, in all, there are
options.
So, attempts are required to find a matching pair if the digital fingerprint is 64 bits long.
128 bits long?
Using the same logic as the first question.
So, attempts are required to find a matching pair if the digital fingerprint is 128 bits long.
Answer:
Step-by-step explanation:
GIVEN : In ΔPQR
S is the mid point of QP
U is the mid point of PR
T is the mid point of QR
Solution :
i) is true i.e
Refer the attached file
By mid segment theorem i.e. In a triangle, the line joining the midpoints of any two sides will be parallel to the third side and that same line joining the midpoints is also half of length of third side .
UT is the line joining the two mid points . So, by theorem given above UT is parallel to PQ and 1/2QP=UT.
So, (i) statement is true i.e.
I believe this is the answer
Might Want to draw this and Its very long but Hope it helped :)
Answer:
The sides are all of the same length - let's say a. The angles are all the same too, and since the angles must add up to 180∘, we conclude that the three angles in the equilateral triangle are equal to 180∘/3=60∘.
Now we do something sneaky. We draw a line all the way down from the top vertex of the triangle to the midpoint of the bottom line.
This new line cuts our equilateral triangle in half. What are the angles in one half?
The angle at the bottom is 90∘.
One of the angles is the same as one of the angles in the original equilateral triangle, so it is 60∘.
So the third angle must be 180∘−90∘−60∘=30∘.
Now the hypotenuse of this new triangle is a, the side length of the equilateral triangle. And the length of the shortest side is a/2, since the line we drew cut the bottom line in half.
Just a guess Bc I’ve no idea what you’re talking abt, but 3. Would set 30/6 and 15/y cross multiply, solve for y and get y =3
