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sergejj [24]
3 years ago
10

In the figure, find the value of x that makes a ∥ b. A. 50° B. 65° C. 75° D. 95°

Mathematics
1 answer:
Natalija [7]3 years ago
6 0

Answer:

is answer is two????????

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Find the perimeter of the quadrilateral.
levacccp [35]

<em><u>Question:</u></em>

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

<em><u>Answer:</u></em>

<h3>The perimeter of the quadrilateral is 129 inches</h3>

<em><u>Solution:</u></em>

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches

The values of the side lengths when x = 2 are

(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch

Perimeter of a quadrilateral = Sum of its sides

Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches

Thus perimeter of the quadrilateral is 129 inches

5 0
3 years ago
Help<br> me please asap
enot [183]

Answer:

first one:

Area of a circle = π*r²

diameter (they gave) = 30ft

radius = diameter/2 = 15ft

π*15²= 706.85834705770347865409476123789‬

to nearest tenth= 706.9 ft

second question:

circumference = 2*π*r or d(diameter)*π

diameter = 30ft

30*π = circumference = 94.247779607693797153879301498385‬

in terms of π = 30π

4 0
3 years ago
F=-GMn/D^2 solve for M
notka56 [123]
M=FD^2/(-Gn) 
here is the solution 

5 0
3 years ago
NEED HELP ASAP! Plz answer all the questions! Including the one on the picture! Will give brainlest!
xeze [42]

-2/3-(-1 1/3) =

-2/3 + 1 1/3 =

4/3 - 2/3 =

<em>2/3</em>

12 - (-5) =

12 + 5 =

<em>17</em>

-1 - (-6) =

-1 + 6 =

6 - 1 =

<em>5</em>

-3 3/8 - 7/8 =

27/8 - 7/8 =

20/8 =

2 4/8 =

<em>2</em><em> </em><em>1/2</em>

4 0
3 years ago
Read 2 more answers
A chord is 10cm from the centre of a circle of radius 15cm. Find the length of the chord.
almond37 [142]

Answer: 21.44 cm

Step-by-step explanation:

Given

Radius r=15 cm

distance of chord from the center is 10 cm

From the figure, the length of the chord is AC

Applying Pythagoras

\Rightarrow AO^2=OB^2+AB^2\\\Rightarrow AB^2=15^2-10^2\\\Rightarrow AB^2=225-100=115\\\Rightarrow AB=\sqrt{115}=10.72\ cm

The length of the chord is AC=2AB=21.44\ cm

5 0
3 years ago
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