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weeeeeb [17]
3 years ago
9

What is the distance between the points (2,-3) and (-6,4) on the coordinate plane

Mathematics
2 answers:
fomenos3 years ago
6 0
Cmon man this is easy‍♂️
Free_Kalibri [48]3 years ago
4 0

Answer:

x=√[(2-(-6))² + (-3-4)²]= 10.63 units

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Write an expression to represent: The sum of four and the product of three and a number x xx.
Ira Lisetskai [31]

Answer:

4+3x

It's pretty straight forward, you have the number 4 that is added to the rest of the expression because sum is addition, and the product of 2 numbers is multiplication so it would make 3(x) or 3x, which results in 4+3x.

8 0
2 years ago
Emily purchased lemons for $600. She sold 3/4 of these at a loss of 20% and the remaining at a gain of 20%. How much percent doe
MAVERICK [17]

Answer:

10%

Step-by-step explanation:

Given: CP of lemon is $600.

           3/4 of lemon sold at 20% loss

           Remaining lemon at 20% gain.

Considering the quantity of lemon remain constant.

Cost price of 3/4 of lemon= \frac{3}{4} \times 600= \$450

As given, 3/4 of lemon sold at 20% loss.

∴ Selling price of \frac{3}{4}\ of\ lemon=  450- \frac{20}{100}\times 450

Selling price= 450- 90= \$ 360

Hence, selling price of 3/4 lemon is $360.

Now, the cost price of remaining lemon (1-\frac{3}{4} )= (\$ 600-\$ 450)

∴ The cost price of \frac{1}{4}\ lemon = \$ 150

As given, remaining \frac{1}{4} lemon\ sold\ at\ gain\ of\ 20\%

∴ Selling price of \frac{1}{4} \ lemon= (150\times \frac{20}{100}+150)

Selling price of \frac{1}{4} \ of\ lemon= (30+150)

Hence, selling price of 1/4 lemon is $180

Loss\profit percent= \frac{(SP-CP)}{CP} \times 100

∴ Loss\profit percent= \frac{60}{600} \times 100= 10\%

Hence, the loss percentage is 10%

8 0
3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
The price of a notebook in 2012 is $2000.
lozanna [386]

First, find 30% of 2,000. To do so you need to convert 30% into a decimal by dividing it by 100.

30% ⇒ 0.30

Now multiply 0.30 by 2,000 to find 30% of 2,000.

2,000 × 0.30 = 600

Subtract 600 from 2,000 to find the price of the notebook in 2013.

2,000 - 600 = 1,400

Now find 30% of 1,400 using the same process.

1,400 × 0.30 = 420

Subtract 420 from 1,400 to find the price of the notebook in 2014.

1,400 - 420 = 980

<h2>Answer:</h2>

<u>The value of the notebook in 2014 is </u><u>$980</u><u>.</u>

7 0
2 years ago
Read 2 more answers
Please help me. I need it!
Yanka [14]

Answer:

znd i cant really tell the numbers on the side

Step-by-step explanation:

i like ur shirt XD

3 0
2 years ago
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