Hello. I could help you with this question because i'm actually learning that too. Just create another question showing the entire graph so that I could help you.
Answer:x=17 y=10
Step-by-step explanation:
No because at the 13 min mark she is at 10.2 not just 10
Answer:
Step-by-step explanation:
a) P(X > 6) = (9.5-6)/(9.5-5.5) = 3.5/4 = 0.875
b) P(X < 7) = (7-5.5)/(9.5-5.5) = 1.5/4 = 0.375
c) E(X) = (9.5+5.5)/2 = 7.5
Standard deviation = (9.5-5.5)/sqrt(12) =4/3.46 = 1.154
P= 1.156*2/(9.5-5.5) = 2.308/4 = 0.577
d) P(X > t) = 0.25
(9.5-t) /(9.5-5.5) = 0.3
9.5-t = 1.2
t = 9.5-1.2 = 8.3
The point (2, 5) is not on the curve; probably you meant to say (2, -5)?
Consider an arbitrary point Q on the curve to the right of P, 
, where 
. The slope of the secant line through P and Q is given by the difference quotient,
where we are allowed to simplify because 
.
Then the equation of the secant line is
Taking the limit as 
, we have
so the slope of the line tangent to the curve at P as slope 2.
- - -
We can verify this with differentiation. Taking the derivative, we get
and at 
, we get a slope of 
, as expected.
