All categories

2 years ago

What is the probability that the guitar neck can be carved between 120 and 200 minutes?

2 answers:

7 0

Unanswerable because you need the information about the skill of the guitar carver. they need to be accounted for their speed in woodworking

inessss [21]2 years ago

3 0

120+80=200 I hope this helped you with your problem

You might be interested in

UGH these math problems tho please help!

Dovator [93]

Answer:

#6 would be 15/7

#7 would be 4/90

#8 would be 17/12

i can't see number 9

#11 would be 65/15 or 4.3333333

31 + 34

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Can anybody help me with my homework please. and explain me how to got the answer. Thanks

natka813 [3]

In the problems A-F, You multiply each of the numbers by itself. Like 9²=9×9=81

3³=3×3×3=27 6³=6×6×6=216 and so on for the other problems

G-I is 36=6² 100=10² and so on the cube is the same except you multiply the number three times by itself. I hope this helped a bit. Just ask if you still don't understand.

8 0

2 years ago

How long is a school bus

Sonja [21]

Answer:

45 ft

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Evaluate the surface integral. s y ds, s is the helicoid with vector equation r(u, v) = u cos(v), u sin(v), v , 0 ≤ u ≤ 6, 0 ≤ v

Juliette [100K]

Compute the surface element:

$\mathrm dS=\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv$

$\vec r(u,v)=(u\cos v,u\sin v,v)\implies\begin{cases}\vec r_u=(\cos v,\sin v,0)\\\vec r_v=(-u\sin v,u\cos v,1)\end{cases}$

$\|\vec r_u\times\vec r_v\|=\sqrt{\sin^2v+(-\cos v)^2+u^2}=\sqrt{1+u^2}$

So the integral is

$\displaystyle\iint_Sy\,\mathrm dS=\int_0^\pi\int_0^6u\sin v\sqrt{1+u^2}\,\mathrm du\,\mathrm dv$

$=\displaystyle\left(\int_0^\pi\sin v\,\mathrm dv\right)\left(\int_0^6u\sqrt{1+u^2}\,\mathrm du\right)$

$=\dfrac23(37^{3/2}-1)$

4 0

2 years ago

The radius of a sphere is increasing at a rate of 2 mm/s. How fast is the volume increasing (in mm3/s) when the diameter is 40 m

daser333 [38]

Answer:

$\dfrac{dV}{dt}=502.65\ mm^3/s$

Step-by-step explanation:

The volume of a sphere is given by :

$V=\dfrac{4}{3}\pi r^3$

The rate of change of volume means,

$\dfrac{dV}{dt}=\dfrac{d}{dt}(\dfrac{4}{3}\pi r^3)\\\\\dfrac{dV}{dt}=\dfrac{4}{3}\pi \times 3r\times \dfrac{dr}{dt}$

We have, $\dfrac{dr}{dt}=2\ mm/s\ and\ r=40\ mm$

So,

$\dfrac{dV}{dt}=\dfrac{4}{3}\pi \times 3\times 20\times 2\\\\=502.65\ mm^3/s$

So, the volume is increasing at the rate of $502.65\ mm^3/s$ .

6 0

3 years ago