- <span>A </span>projectile<span> is </span>thrown upward so<span> that </span>its distance above<span> the </span>ground after t seconds<span> is </span>given<span> by the </span>function h(t<span>) = - 16t² + </span>640t<span>. </span>After<span> how </span>many seconds<span> does the </span>projectile<span>take</span><span> to reach </span>its<span> maximum height? I made the </span>function<span> .</span>
Y = 3x + 3 this is equation 1
y = x -1 this is equation 2
since equation 1 and 2 already defined y in terms of x, we're just gonna substitute y into the other equation. as 2 is shorter I'm going with that today
x - 1 = 3x +3
-1 - 3 = 3x - x
-4 = 2x
x = -2
now we've got x just sub it in equation 2
y = -2 -1
y = -3
so the answer is (-2,-3)
Answer:
(-3, 1), 5
Step-by-step explanation:
x² + y² + 6x - 2y - 15 = 0
Rearrange:
x² + 6x + y² - 2y = 15
Complete the square:
x² + 6x + 9 + y² - 2y + 1 = 15 + 9 + 1
(x + 3)² + (y - 1)² = 25
Therefore, the center is (-3, 1) and the radius is 5.
Answer:
1) f(x) = x/8 - 7
2) f(x) = 1 - x/3
3) f(x) = 20 - 0.25x
4) f(x) = x + 7
Step-by-step explanation:
f^-1 = 8(x + 7)
x + 7 = y/8
x = y/8 - 7
f(x) = x/8 - 7
f^-1 = -3(x - 1)
y/-3 = x - 1
x = 1 - y/3
f(x) = 1 - x/3
f^-1 = 4(20 - x)
y/4 = 20 - x
x = 20 - y/4
f(x) = 20 - x/4
f(x) = 20 - 0.25x
f^-1 = x - 7
y = x - 7
x = y + 7
f(x) = x + 7
