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anyanavicka [17]
3 years ago
6

Kiara drew a scale drawing of an apartment. The scale of the drawing was 11 millimeters : 4 meters. The actual length of the din

ing room is 8 meters. How long is the dining room in the drawing?
Mathematics
1 answer:
melamori03 [73]3 years ago
7 0

Answer:

22 millimeters

Step-by-step explanation:

Given that:

Scale of drawing = 11 millimeters : 4 meters

This means 4 meters of actual is represented as 11 millimeters on the drawing

If actual length of dining room = 8 meters ;

Lenght of dinning room in drawing will be x :

11 millimeters = 4 meters

X millimeters = 8 meters

Cross multiply :

4*x = 11 * 8

4x = 88

x = 88/4

x = 22

Hence, the length of the drawing will be 22 millimeters

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2 3/8 - (-2 7/8) figure this out before the end of the day please
Fantom [35]

Answer:

5 1/4

Step-by-step explanation:

Subtracting a negative is the same as adding a positive.

2 3/8 - (-2 7/8) =

= 2 3/8 + 2 7/8

= 4 10/8

= 4 + 8/8 + 2/8

= 4 + 1 + 1/4

= 5 1/4

4 0
3 years ago
Necesito que me ayuden con unas tareas de matematicas de primer grado de secundaria​
Alex_Xolod [135]

Answer: i don't know

Step-by-step explanation:

                               

5 0
3 years ago
Solve for x:a(a²+b²)x²+b²x-a​
m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a  

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b²  = (b² + 2a²)²

2. Solve for x

\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}

\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}

5 0
3 years ago
An artist plans to sell $300 of prints online each week. This month, she is within $22 of her goal.
monitta

The minimum and maximum amounts that the artist received for her products are 278 and 322

<h3>Part A: Define a variable and write an absolute value equation to represent the scenario.</h3>

Let the number of prints remaining be x.

The given parameters are:

Total = 300

Amount = 22 within her goal

So, we have the following absolute value equation

|x - 300| = 22

<h3>Part B: Solve the equation, showing all steps.</h3>

In (a), we have:

|x - 300| = 22

Remove the absolute bracket

x - 300 = 22 and x - 300 = -22

Add 300 to both sides

x = 322 and x = 278

<h3>Part C: What are the minimum and maximum amounts that the artist received for her products?</h3>

The minimum and maximum amounts that the artist received for her products are 278 and 322

Read more about absolute value equation at

brainly.com/question/17795998

#SPJ1

3 0
2 years ago
8.42 Three bags of jelly beans contain 26,28 , and 30 beans. In each bag, the percent of the beans that are yellow is 50%, 25%,
olasank [31]

Answer:

Step-by-step explanation:

Figure out the number of yellow beans in each bag:

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Bag B: 0.25*28 = 7 beans

Bag C: 0.2*30 = 6 beans

The total number of beans in the bowl: 26+28+30 = 84

Total number of yellow beans: 13+7+6 = 26

Percentage of yellow beans: 26/84 *100 = 30.9523

Rounded answer: 31%

6 0
2 years ago
Read 2 more answers
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