What's the question here?
1.
lim x→ 0+ f(x)
you will find the limit is inf
lim x→ 0- f(x)
you will find the limit is - inf
because
lim x→0+ f(x) no equal to lim x→0- f(x)
thus lim x→0 f(x) does not exist
2.
form the graph
lim x→2- f(x) = 6
lim x→2+ f(x)= -2
because
lim x→2- f(x) not equal tolim x→2+ f(x)
thus lim x→2 f(x) does not exist
hope this would help you.
Answer:
The inner function is
and the outer function is
.
The derivative of the function is
.
Step-by-step explanation:
A composite function can be written as
, where
and
are basic functions.
For the function
.
The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.
Here, we have
inside parentheses. So
is the inner function and the outer function is
.
The chain rule says:
![\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%3Df%27%28g%28x%29%29g%27%28x%29)
It tells us how to differentiate composite functions.
The function
is the composition,
, of
outside function: 
inside function: 
The derivative of this is computed as

The derivative of the function is
.
True... is there any specific to your question?
Answer:
128; 137
Step-by-step explanation:
Plug the arm span into the formula