Given:
Angle A is circumscribed about circle O.
m∠CDB = 48°
To find:
The measure of angle A.
Solution:
OC and OB are radius of circle O.
AC and AB are tangents of circle O.
The angle between tangent and radius is always 90°.
⇒ m∠OCA = 90° and m∠OBA = 90°
The angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.
⇒ m∠COB = 2 × m∠CDB
⇒ m∠COB = 2 × 48°
⇒ m∠COB = 96°
Sum of all the angles of quadrilateral is 360°.
m∠BAC + m∠OCA + m∠COB + m∠OBA = 360°
m∠BAC + 90° + 96° + 90° = 360°
m∠BAC + 276° = 360°
Subtract 276° from both sides.
m∠BAC = 84°
The measure of ∠A is 84°.
Answer:
1344/19 =x or 70 14/19
Step-by-step explanation:
y=19x - 1,344
to find the x intercept set y = 0 and solve for x
0 = 19x - 1344
ad 1344 to each side
1344 = 19x-1344+1344
1344= 19x
divide by 19
1344/19 = 19x/19
1344/19 =x
Answer:
Step-by-step explanation:
(x - 5)(x-4)
= x(x) - 4(x) - 5(x) - 4(-5)
= x^2 - 4x - 5x + 20
= x^2 - 9x + 20
Here’s how to solve:
3x-15+-9
3x-24
The correct answerr is 48
