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Rudik [331]
4 years ago
8

URGENT! 20 POINTS

Mathematics
1 answer:
Nonamiya [84]4 years ago
5 0

Answer:

128; 137

Step-by-step explanation:

Plug the arm span into the formula

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Identify the geometric mean of 3 and 48. HELP ASAP!!<br><br> 19<br> 144<br> 12<br> 16
vekshin1
C ; 12 i think
or
B ; 144
3 0
3 years ago
The vertices of a triangle are listed below. E(-1, 2), F(-5, -1), G(-1, -4) What is the area of the triangle? A. 24 square units
pentagon [3]

Answer:

B. 12 square units

Step-by-step explanation:

5 0
4 years ago
I am just completely lost and am unsure of how to approach this problem.
Anastasy [175]

Answer:

68°

Step-by-step explanation:

As BA⊥BD, so ∠ABD = 90°

also, ∠ABD = ∠CBD + ∠ABC

⇒ 90° = 4x + 52° + 8x - 10°

⇒  12x = 48°

⇒  x = 4°

now,

∠CBD = 4x + 52°

          = 4(4°) + 52°

          = 68°

5 0
3 years ago
A rectangle is three centimeters.longer than it is wide. if its length were to be decreased by two centimeters, its area would d
Scorpion4ik [409]
Given/equations formed from text:
I: l=w+3
II: A=l*w
III: new area B=(l-2)*w
IV: B=A-30

substitute l in II with I to remove l:
II': A=l*w=
(w+3)*w=
w^2+3w

substitute l in III with I to remove l:
III': B=(l-2)*w=
(w+3-2)*w=
(w+1)*w=
w^2+w

substitute A and B from II' and III' into IV:
B=A-30
w^2+w=w^2+3w-30
30=2w
w=15

insert w=15 into I:
l=15+3=18
->
A) dimensions of full size rectangle are width 15 and length 18
dimensions of reduced size rectangle are width 15 and length 16

B) full size: 15*18=10*18+5*18=180+90=270cm^2
reduced size: 15*16=10*16+5*16=160+80=240cm^2


7 0
4 years ago
Someone please help me w this standard form question​
svp [43]

Answer:

2.4 × 10⁶

Step-by-step explanation:

Given:

  • \sf x=3.8 \times 10^5
  • \sf y=5.9 \times 10^4

To calculate the value of R, substitute the given values into the given formula:

\begin{aligned}\sf R & = \sf \dfrac{x^2}{y}\\\\ \implies \sf R& = \sf \dfrac{(3.8 \times 10^5)^2}{5.9 \times 10^4}\\\\& = \sf \dfrac{3.8^2 \times (10^5)^2}{5.9 \times 10^4}\\\\& = \sf \dfrac{14.44 \times 10^{10}}{5.9 \times 10^4}\\\\& = \sf \dfrac{14.44}{5.9} \times \dfrac{10^{10}}{10^4}\\\\& = \sf 2.4474... \times 10^{(10-4)}\\\\& = \sf 2.4474... \times 10^6\\\\\end{aligned}

Therefore, the value of R to 1 decimal place is 2.4 × 10⁶

--------------------------------------------------------------------------

<u>Exponent Rules used</u>

(a^b)^c=a^{bc}

{a^b}{a^c}=a^{b-c}

3 0
2 years ago
Read 2 more answers
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