Answer:
2 terms
Step-by-step explanation:
Terms are nothing but the mixtures of co-effecients and their variables..
Here, 9a is one term while 11p is the other
Answer:
I don't know bro actually which question ❓
Option c would be correct
<h2>
Answer:</h2>
The values of x for which the given vectors are basis for R³ is:

<h2>
Step-by-step explanation:</h2>
We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.
We are given three vectors as:
(-1,0,-1), (2,1,2), (1,1, x)
The matrix formed by these vectors is:
![\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%262%261%5C%5C0%261%261%5C%5C-1%262%26x%5Cend%7Barray%7D%5Cright%5D)
Now, the determinant of this matrix is:

Hence,

29 is a prime number.
Factors of 29: 1 , 29
168 is a composite number, therefore you can find the prime factorization for it. Divide prime factors until what is left is a prime number. Use the tree factor. See attached picture:
Prime factorization of 168: 2, 2, 2, 3, 7