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3 years ago

8

A pair of equations is shown below.

2 answers:

Delicious77 [7]3 years ago

7 0

X+y=5
y=x/2 +2
We have to solve this system of equations:
we can solve by substitution method.
y=x/2 +2

x+(x/2 + 2)=5
2x+x+4=10 (lowest common multiplo =2)
3x=10-4
3x=6
x=6/3=2

y=x/2 +2 =2/2 +2=1+2=3

Then:
x=2 and y=3 ⇒(2,3)

Answer: the point is (2,3)

Murljashka [212]3 years ago

5 0

Answer:(2,3) is correct

Step-by-step explanation:

Got it right on quiz

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irina1246 [14]

Answer:

The amount of ounce used for paint is $\frac{9}{15} ounce$

Step-by-step explanation:

used amount for water is $\frac{2}{3}$ ounce.

used amount for sky is $\frac{3}{5}$ ounce.

thus, the total amount used is $\frac{2}{3}$ + $\frac{3}{5}$

= $\frac{19}{15}$

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But the remaining amount is $\frac{2}{15}$ .

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3 years ago

What is 600 is 10 times as much as

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4 years ago

Use the appropriate substitutions to write down the first four nonzero terms of the Maclaurin series for the binomial (1+3x)^(-1

PolarNik [594]

Answer:

First term=1

Second term=-x

Third term= $2x^2$

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Step-by-step explanation:

We are given that function

$f(x)=(1+3x)^{-1/3}$

We have to find the first four non zero terms of the Maclaurin series for the binomial.

Maclaurin series of function f(x) is given by

$f(x)=f(0)+f'(0)x+\frac{1}{2!}f''(0)x^2+\frac{1}{3!}f'''(0)x^3+....$

$f(0)=(1+3x)^{\frac{-1}{3}}=1$

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$f'(0)=-1$

$f''(x)=\frac{4}{3}\times 3 (1+3x)^{-\frac{7}{3}}$

$f''(0)=4$

$f'''(x)=-4\times \frac{7}{3}\times 3(1+3x)^{-\frac{10}{3}}$

$f'''(0)=-28$

Substitute the values we get

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First term=1

Second term=-x

Third term= $2x^2$

Fourth term = $-\frac{28}{3!}x^3$

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