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astraxan [27]
3 years ago
8

A pair of equations is shown below.

Mathematics
2 answers:
Delicious77 [7]3 years ago
7 0
X+y=5
y=x/2  +2
We have to solve this system of equations:
we can solve by substitution method.
y=x/2 +2

x+(x/2  + 2)=5
2x+x+4=10    (lowest common multiplo =2)
3x=10-4
3x=6
x=6/3=2

y=x/2  +2 =2/2 +2=1+2=3

Then:
x=2 and y=3  ⇒(2,3)

Answer: the point is (2,3)
Murljashka [212]3 years ago
5 0

Answer:(2,3) is correct

Step-by-step explanation:

Got it right on quiz

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3 years ago
Choose all that are correct.
NeTakaya

Answer:

C

Step-by-step explanation:

7 0
3 years ago
Suppose the probability of being picked first in your class is 0.05. What are the the odds of being picked first? Express your a
den301095 [7]

Suppose the probability of being picked first in your class is 0.05. The odds of being picked first expressed in form of a: b is 1 : 19.

A probability is a number that represents the possibility or chance that a specific event will occur.

{\mathbf{\text{The probability of an event} = \dfrac{\text{number of desired outcome}}{\text{total number of possible outcome}}}

From the given information;

  • Let assume the total number of people in the class is whole = 1

∴

The odds of being picked first can be computed as:

\mathbf{=\dfrac{0.05}{1-0.05}}

\mathbf{=\dfrac{0.05}{0.95}}

\mathbf{\dfrac{1}{19}}

= 1 : 19

Therefore, the odds of being picked first in terms of a: b is 1 : 19

Learn more about probability here:

brainly.com/question/11234923?referrer=searchResults

5 0
2 years ago
Kevin will take 4 math tests this term. All of the tests are worth the same number of points. After taking the first 3 tests, hi
Makovka662 [10]

Answer:

Kevin needs 96 points on his last test to raise his mean test score to 90 points.

Step-by-step explanation:

we know that

The mean score is the total of all scores divided by the total number of tests.

Let

x_1 ----> the score in the first math test

x_2 ----> the score in the second math test

x_3 ----> the score in the third math test

x_4 ----> the score in the fourth math test

we have

After taking the first 3 tests, his mean test score is 88 points

so

\frac{x_1+x_2+x_3}{3} =88

x_1+x_2+x_3=264 ----> equation A

How many points does he need on his last test to raise his mean test score to 90 points?

so

\frac{x_1+x_2+x_3+x_4}{4} =90

x_1+x_2+x_3+x_4=360 ----> equation B

substitute equation A in equation B

264 + x_4 = 360

solve for x_4

x_4 = 360-264

x_4 = 96

Therefore

Kevin needs 96 points on his last test to raise his mean test score to 90 points.

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4 years ago
Determine the domain of each piece. Domain of piece 1:[ ) Domain of piece 2: [ ) Domain of piece 3
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