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2 years ago

Mateo reproducira una foto que mide 5 cm por lado a una escala de 3/4

Mathematics

1 answer:

Aneli [31]2 years ago

3 0

the question in English

Mateo will reproduce a photo measuring 5 cm per side on a scale of 3/4

How much will the square side of the copy measure?

Will the size of the copy be larger or smaller than the original?

we know that

the scale factor is equal to $\frac{3}{4}$

Let

x----------> the original length side

y--------> the copy length side

$y=\frac{3}{4}*x$

we have that

$x=5\ cm$

substitute the values

$y=\frac{3}{4}*5=3.75\ cm$

therefore

<u>the answer Part a) is </u>

the length side of the copy measure is $3.75\ cm$

Part b)

we know that

the size of the original photo is------> $5*5=25\ cm^{2}$

the size of the copy is------> $3.75*3.75=14.06\ cm^{2}$

$14.06\ cm^{2} < 25\ cm^{2}$

therefore

<u>the answer part b) is</u>

The size of the copy be smaller than the original

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Answer:

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C. $y+6=3(x-15)$

Step-by-step explanation:

Given:

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$6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}$

Therefore, the slope of the line is $m=-\frac{1}{3}$ .

Now, for perpendicular lines, the product of their slopes is equal to -1.

Let us find the slopes of each lines.

Option A:

$y=3x-10$

On comparing with the slope-intercept form, we get slope as $m_{A}=3$ .

Now, $m\times m_{A}=-\frac{1}{3}\times 3=-1$ . So, option A is perpendicular to the given line.

Option B:

For lines of the form $x=a$ , where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as $m_{C}=3$ .

Now, $m\times m_{C}=-\frac{1}{3}\times 3=-1$ . So, option C is perpendicular to the given line.

Option D:

$3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}$

On comparing with the slope-intercept form, we get slope as $m_{D}=-\frac{1}{3}$ .

Now, $m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}$ . So, option D is not perpendicular to the given line.

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2 years ago

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3 years ago

Help with this question please?

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