5. From 13 friends to 14 friends

Graph the image of the given triangle under a dilation with a scale factor of 12 and the center of dilation (0, 0) .

PilotLPTM [1.2K]

Answer:

brainly.com/question/10891847

Step-by-step explanation:

4 0

2 years ago

The prices of consumer goods do not always exactly follow the CPI. The following chart shows several consumer items, along with

zloy xaker [14]

The reasonable estimate of the current customer price index is 195. The option B is the correct option.

<h3>Customer price index</h3>

Customer price index is the price index which measures the weight average of price of basket of customers goods or services.

It can be given as,

$\rm CPI_t=\dfrac{C_t}{C_0}\times 100$

Here $\rm C_t$ is the cost of market basket in current period and $\rm C_0$ is the cost of market basket in the base period.

Cost of market basket in current period is

$\rm C_t=15.66+119.75+23.99+37.50\\\\C_t=196.9$

Cost of market basket in 1983 is,

$\rm C_0=8.85+71.25+13.95+22.7\\\\C_0=116.8$

Substitute all the values in the formula

$\rm CPI_t=\dfrac{C_t}{C_0}\times 100\\\\\rm CPI_t=\dfrac{196.9}{116.8}\times 100\\\\\rm CPI_t=1.685\times 100 \\\\ CPI_t=168.5\\\\\rm CPI_t= 170 \ \rm approx$

Thus the value of current CPI is 168.5 which is near about the 170.

Hence, the reasonable estimate of the current customer price index is 195. The option B is the correct option.

Learn more about the customer price index here;

brainly.com/question/25495502

3 0

2 years ago

a rectangle measures 3 yards by 4 feet what is the perimeter of the rectangle in inches show your work please

marissa [1.9K]

Length: 3 yds. 36 in= 1 yd; 108 in.=3 yds
Width: 4 ft. 12 in=1 ft.; 48 in= 4 ft.
Sinve there are two lengths and widths in a rectangle, I like to multiply them both by 2 and add up the results. You also get the same answer when you add everything up twice. My answer is 312 in.

7 0

3 years ago

Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar

Mamont248 [21]

Answer:

a

The 95% confidence interval is

$0.7811 < p < 0.9529$

Generally the interval above can interpreted as

There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval

b

Generally 99% is outside the interval obtained in a above then the claim of Wal-mart is not believable

c

$n = 125 \ stores$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The number of stores that had more than 2 items price incorrectly is k = 52

Generally the sample proportion is mathematically represented as

$\^ p = \frac{ k }{ n }$

=> $\^ p = \frac{ 52 }{ 60 }$

=> $\^ p = 0.867$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.96 * \sqrt{\frac{ 0.867 (1- 0.867)}{60} }$

=> $E = 0.0859$

Generally 95% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.867 - 0.0859 < p < 0.867 + 0.0859$

=> $0.7811 < p < 0.9529$

Generally the interval above can interpreted as

There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval

Considering question b

Generally 99% is outside the interval obtained in a above then the claim of Wal-mart is not believable

Considering question c

From the question we are told that

The margin of error is E = 0.05

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$