Answer:
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 16 - 1 = 15
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.9467
The margin of error is:
M = T*s = 2.9467*0.058 = 0.171
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg
The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
For this case we have that the cost of each pizza is given by the following function:

Where:
r: It's the radius of the pizza
IF a pizza cost $26.32 we have:

We cleared the radius, using
:

We choose the positive value:

So, the radius of the pizza is 
Then, the diameter is: 
Finally, the diameter of the pizza is:
Answer:
Option B
Answer:
Step-by-step explanation:
I don't think this can be done without the diagram. You do not know what HD is opposite. I will take a guess that it is opposite TU which makes TU = 220 because both H and D are midpoints and that makes TU twice as large as HD.
If this is incorrect, post the diagram.
I'm not sure why options a. and d. are the same, but you would simply count the number of times x and m appear, while being multiplied together, and multiply the product of xm by that number. in this case, the number is 7, so you should get 7(xm) or 7xm.
Answer:
The image will be DCBAFE
Step-by-step explanation:
A polygon with six sides is called a hexagon
In this question first identify the midpoints of BC and EF using perpendicular bisector.
This should be followed by joining the two midpoints with a straight edge to draw the mirror line.
The points above the mirror line F,A and B will be reflected below the mirror line.The points below the mirror line C,D and E will be reflected above the mirror line.
The image will be DCBAFE