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3 years ago

6

The cost of a student ticket is $7 write a equation that correctly relates the total cost

1 answer:

daser333 [38]3 years ago

6 0

X=$7 | 1 Ticket= x | 1 Ticket = $7

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If 48% of the students in a certain college are female and there are 1440 female students, what is the total number of students

Andrews [41]

Answer:

3000 students

Step-by-step explanation:

If 48% of the students are female, and there are 1440 female students, we can set up a percentage proportion, assuming x is the total amount of students.

$\frac{1440}{x} = \frac{48}{100}$

We can use the cross products property to find the value of x.

$1440\cdot100=144000\\\\144000\div48=3000$

Hope this helped!

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3 years ago

Which expression is equivalent to 9p+9p

mafiozo [28]

Answer:

18p? I don't know what other expressions could be equivalent. I just added 9p to 9p to get my answer.

8 0

2 years ago

A jeweler has 36 inches of silver chain. She needs 5 time that much to make some necklaces. How much silver chain does the jewel

Elina [12.6K]

36 *<span> 5 = 180
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4 0

2 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

So

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

2 years ago

The expression to find the perimeter of a rectangle is 2(length + width). What is the perimeter, in units, of a rectangle of len

harina [27]

Answer:

OPTION B

$1\frac{2}{7}units$

Step-by-step explanation:

1. You have the following formula for calculate the perimeter of a rectangle:

$P=2(l+w)$

Where l is the lenght and w i the width.

2. Therefore, if the rectangle has the following dimensions:

$l=\frac{1}{7}units\\\\w=\frac{1}{2}units$

You can substitute these values into the formula shown above to calculate the perimeter of a rectangle. Therefore, you obtain the following result:

$P=2(\frac{1}{7}units+\frac{1}{2}units)=\frac{9}{7}units$ or $1\frac{2}{7}units$

5 0

2 years ago

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