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NikAS [45]
3 years ago
14

The ratio of males to females in a cycling club is 5:3.

Mathematics
1 answer:
taurus [48]3 years ago
6 0

Answer:

3/2

Step-by-step explanation:

The ratio of males to females in a cycling club is 5:3.

1/3 of the males are under 18

2/9 of the females are under 18

The fraction of the club members that are under 18 is calculated as:

Male: Female = Male/Female

We are told in the above question:

1/3 of the males are under 18

2/9 of the females are under 18

Hence:

1/3 / 2/9

= 1/3 ÷ 2/9

= 1/3 × 9/2

= 3/2

The fraction of the club members that are under 18 is 3/2

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14 less than the quotient of 63 and a number h
ycow [4]
<span>quotient of 63 and a number h would be 63/h
14 less than that would be 63 over h - 14</span>
8 0
3 years ago
Read 2 more answers
Which expressions are equivalent to 6 (–x) 2x (–7) 2x? Check all that apply. X x 6 – 7 x 2x 2 x 3 – x 2x – 4 2x x – 1 x 1.
qaws [65]

Equivalent expression is the expression which is equal to the original equation but the way of representation is different. The equivalent expression of the given expression are,

x+x+6-7+x

3-x+2x-4+2x=3x-1

Given information

The given expression in the problem is,

6+(-x)+2x+(-7)+2x

<h3>Equivalent expression</h3>

Equivalent expression is the expression which is equal to the original equation but the way of representation is different.

The given equation is,

6+(-x)+2x+(-7)+2x

As the product of the negative and positive is negative. Thus solve the equation by opening the bracket.

6+(-x)+2x+(-7)+2x=6-x+2x-7+2x\\&#10;6+(-x)+2x+(-7)+2x=-x+2x+2x+6-7\\&#10;6+(-x)+2x+(-7)+2x=3x-1

Check all the option,

  • 1) The expression given in the option 1 is,

x+x+6-7+x

Solve it further,

x+x+6-7+x=x+x+x+6-7\\&#10;x+x+6-7+x=3x-1\\

The result is equal to the result of the given expression. Thus the expression of the option 1 is equivalent to the expression given in the problem.

  • 2) The expression given in the option 2 is,

2x+2+x

Solve it further,

2x+2+x=2x+x+2\\2x+2+x=3x+2

The result is not equal to the result of the given expression. Thus the expression of the option 2 is not equivalent to the expression given in the problem.

  • 3) The expression given in the option 3 is,

3-x+2x-4+2x

Solve it further,

3-x+2x-4+2x=3x-1

The result is equal to the result of the given expression. Thus the expression of the option 3 is equivalent to the expression given in the problem.

  • 4) The expression given in the option 4 is,

x-1

The expression of the option 4 is not equivalent to the expression given in the problem.

  • 5) The expression given in the option 4 is,

x+1

The expression of the option 5 is not equivalent to the expression given in the problem.

Hence the equivalent expression of the given expression are,

x+x+6-7+x

3-x+2x-4+2x=3x-1

Learn more about the equivalent expression here;

brainly.com/question/10628562

7 0
2 years ago
Read 2 more answers
Please help and thank you
nalin [4]

Answer:

Your answer is D. Hoped i helped

Step-by-step explanation:

plot each coordinate, Then see which has the most/all in the shaded area.

4 0
2 years ago
Plssssss help me show the work!!
PilotLPTM [1.2K]

Answer:

use the quadruple double schlop schlop theorum

Step-by-step explanation:

Factor  

25

out of  

50

.

3

√

25

(

2

)

Rewrite  

25

as  

5

2

.

3

√

5

2

⋅

2

Pull terms out from under the radical.

3

(

5

√

2

)

Multiply  

5

by  

3

.

15

√

2

The result can be shown in multiple forms.

Exact Form:

15

√

2

Decimal Form:

21.21320343

3 0
3 years ago
If ex + e*-1= 2, then x =..
lianna [129]

<em>Note: Your equation seems a little unclear. But, I am assuming that your equation is:</em>

e^x\:+\:e^{-1}=\:2

<em>Because my solution would still clear your concept about this topic, no matter what the question is.</em>

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equation

e^x\:+\:e^{-1}=\:2

subtract e^{-1} from both sides

e^x+e^{-1}-e^{-1}=2-e^{-1}

e^x=2-\frac{1}{e}

\ln \left(e^x\right)\:=\ln \:\left(2-\frac{1}{e}\right)

\:x\cdot ln\left(e\right)=\ln \:\:\left(2-\frac{1}{e}\right)

\:x\cdot 1=\ln \:\left(2-\frac{1}{e}\right)       ∵ \:\:\ln \left(e\right)=1

x=\ln \:\left(2-\frac{1}{e}\right)    

x=0.5

8 0
2 years ago
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