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3 years ago

The ratio of males to females in a cycling club is 5:3.

Mathematics

1 answer:

taurus [48]3 years ago

6 0

Answer:

3/2

Step-by-step explanation:

The ratio of males to females in a cycling club is 5:3.

1/3 of the males are under 18

2/9 of the females are under 18

The fraction of the club members that are under 18 is calculated as:

Male: Female = Male/Female

We are told in the above question:

1/3 of the males are under 18

2/9 of the females are under 18

Hence:

1/3 / 2/9

= 1/3 ÷ 2/9

= 1/3 × 9/2

= 3/2

The fraction of the club members that are under 18 is 3/2

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Points A, B, C, and D are collinear and positioned in that order. Find the length indicated 7) Find BC if BC = 2x + 4, AD = 28,

belka [17]

Answer:

7) BC = 10

8) BD = 20

Step-by-step explanation:

7) The segment addition theorem tells you ...

AB +BC +CD = AD

(3x+2) +(2x+4) +(3x-2) = 28

8x +4 = 28 . . . . collect terms

8x = 24 . . . . . . . subtract 4

x = 3 . . . . . . . . . divide by 8

BC = 2x+4 = 2(3) +4

BC = 10

8) AB +BD = AC +CD

(2x -14) +(-7 +3x) = (2x -3) +(9)

5x -21 = 2x +6

3x = 27

x = 9

BD = -7 +3x = -7 +3(9)

BD = 20

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3 years ago

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Answer:

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2 years ago

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Slove step-by-step (5+4)×2+6-(2×2)-1

Sladkaya [172]

1. (5 + 4) x 2 + 6 - (2 x 2) - 1
2. 9 x 2 + 6 - 4 - 1
3. 18 + 6 - 4 - 1
4. 24 - 4 - 1
5. 20 - 1
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2 years ago

To save money, a local charity organization wants to target its mailing requests for donations to individuals who are most suppo

mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - α) % confidence interval for difference between two means is:

$CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}$

Given:

$\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25$

Confidence level = 80%

$t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397$

*Use a t-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

$CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)$

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

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2 years ago

What is 2160 minus 1600 long way

lilavasa [31]

Hey there, Lets solve this problem together.

The First step is to line up the numbers.

$= 2160

- 1600$

$\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}$

We calculate $0-0$ the result of which is $0$ 

We calculate $6-0$ the result of which is $6$ .

Since we get a negative number in the next column, we must take 1 from the next column and carry it over to this column. Now the number will be changed to 10.

We calculate $10+1-6$ , and the result is $5$ .

We calculate $2-1-1$ the result of which is $0$ .

Therefore,

$2160 - 1600 = 0560$

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2 years ago