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3 years ago

Can Someone Help me with my Algabra 2 Homework 4a-c

Mathematics

1 answer:

kicyunya [14]3 years ago

6 0

Answer:

Step-by-step explanation:

Sigma notation is:

∑ ak

k=1

The n on top is the number of terms. ak is the expression for the kth term.

Let's look at the first one. The series is:

-2+4+-8+...+64+-128

There's two things to notice. One, the sign changes back and forth between + and -. Two, the magnitude doubles with each next term. Therefore:

ak = (-2)ᵏ

Next we need to find the number of terms. -128 is the last term, so:

128 = 2ⁿ

n = 7

So the answer is:

∑ (-2)^k

k=1

Now the second one. Notice the numerators are all 1 and the denominators are all perfect squares. Therefore:

ak = (1/k)²

The last term is 1/100, so n = 10.

So the answer is:

∑ (1/k)²

k=1

Now the last one. Notice that each term is 5 plus the previous term. This is an arithmetic series. So we can say:

ak = 4 + 5(k-1)

ak = 4 + 5k - 5

ak = 5k - 1

The last term is 49, so:

49 = 5n - 1

n = 10

So the answer is:

∑ (5n-1)

k=1

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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

Write the equation in slope-intercept form for each line based on the information given.

nexus9112 [7]

Answer:

y = -1x + 6 or y = -x + 6

Step-by-step explanation:

First, let's identify what slope-intercept form is.

y = mx + b

m is the slope. b is the y-intercept.

We know the slope is -1, so m = -1. Plug this into our standard equation.

y = -1x + b

To find b, we want to plug in a value that we know is on this line: (2, 4). Plug in the x and y values into the x and y of the standard equation.

4 = -1(2) + b

To find b, multiply the slope and the input of x(2)

4 = -2 + b

Now, add 2 from both sides to isolate b.

6 = b

Plug this into your standard equation.

y = -1x + 6

This is your equation.

Check this by plugging in the point again.

y = -1x + 6

4 = -1(2) + 6

4 = -2 + 6

4 = 4

Your equation is correct.

Hope this helps!

8 0

3 years ago

If you know the answer tell me please and if you do you would be the best

Butoxors [25]

11 ⅓ gallons.

Explanation:

Since she sold 3⅓ gallons more on Sunday than she did on Saturday, you need to add 10⅔+3⅓. ⅓+⅔=3/3, or 1. 10+3=13, and 13+1=14. She sold 14 gallons on Sunday.

On Monday, she sold 2⅔ less than she did on Sunday, so we need to do 14-2⅔. 14-2 is 12, and 12-⅔= 11⅓. This means that she sold 11⅓ gallons on Monday.

Hope this helps :)

5 0

3 years ago

Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is $[ {\rm{\$ 10,000 , \$ 15,000}]$ , where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

$\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}$

$=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4$

(b) The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

$\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)$

$=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8$

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

$\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}$

(d) The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

5 0

3 years ago

Evaluate ....................

SCORPION-xisa [38]

Answer:

(-1)*(-1)=1

1*(-1)= -1

first option (-1) is the right answer.

3 0

3 years ago

Can Someone Help me with my Algabra 2 Homework 4a-c​

Can Someone Help me with my Algabra 2 Homework 4a-c