write an equation to represent the oxidation of an alcohol.
identify the reagents that may be used to oxidize a given alcohol.
identify the specific reagent that is used to oxidize primary alcohols to aldehydes rather than to carboxylic acids.
identify the product formed from the oxidation of a given alcohol with a specified oxidizing agent.
identify the alcohol needed to prepare a given aldehyde, ketone or carboxylic acid by simple oxidation.
write a mechanism for the oxidation of an alcohol using a chromium(VI) reagent.
The reading mentions that pyridinium chlorochromate (PCC) is a milder version of chromic acid that is suitable for converting a primary alcohol into an aldehyde without oxidizing it all the way to a carboxylic acid. This reagent is being replaced in laboratories by Dess‑Martin periodinane (DMP), which has several practical advantages over PCC, such as producing higher yields and requiring less rigorous reaction conditions. DMP is named after Daniel Dess and James Martin, who developed it in 1983.
This page looks at the oxidation of alcohols using acidified sodium or potassium dichromate(VI) solution. This reaction is used to make aldehydes, ketones and carboxylic acids, and as a way of distinguishing between primary, secondary and tertiary alcohols.
Oxidizing the different types of alcohols
The oxidizing agent used in these reactions is normally a solution of sodium or potassium dichromate(VI) acidified with dilute sulfuric acid. If oxidation occurs, the orange solution containing the dichromate(VI) ions is reduced to a green solution containing chromium(III) ions. The electron-half-equation for this reaction is
Cr2O2−7+14H++6e−→2Cr3++7H2O
Answer: 24 gram is a final Answer.
Explanation:1 mol of carbon weight is 12 gram then
12.044×1023 contain 2 mole carbon so
The number of moles of oxygen in the gas is 1.5 L.
The correct option is (A).
<h3>What are moles? </h3>
The mole is the International System of Units' foundation unit of material quantity.
Given,
The volume of gas is 33.6 L
Pressure is 1 atm.
Temperature is 0°C
Molar gas volume is 22.4 L
There is no temperature and pressure is 1 atm.
By formula of moles, volume is divided by molar mass
Thus, option A is correct. 1.5 L.
Learn more about gas, here:
brainly.com/question/13123721
Answer:
the answer is d hope this helps
and dont forget to mark me as brainliest
Explanation:
Answer:
at 181.0 
is -723.3 kJ/mol.
Explanation:
We know, 
where, T is temperature in kelvin.
Let's assume 
and 
does not change in the temperature range 25.0 - 181.0 .
= (273+181.0) K = 454.0 K
Hence, at 181.0 , ![\Delta G^{0}=(-795.8kJ/mol)-[(454.0 K)\times (-159.8\times 10^{-3}kJ/K.mol)]](https://tex.z-dn.net/?f=%5CDelta%20G%5E%7B0%7D%3D%28-795.8kJ%2Fmol%29-%5B%28454.0%20K%29%5Ctimes%20%28-159.8%5Ctimes%2010%5E%7B-3%7DkJ%2FK.mol%29%5D)
= -723.3 kJ/mol
