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const2013 [10]
3 years ago
11

The value of ΔG° at 181.0 °C for the formation of calcium chloride from calcium metal and chlorine gas is ________ kJ/mol. At 25

.0 °C for this reaction, ΔH° is -795.8 kJ/mol, ΔG° is -748.1 kJ/mol, and ΔS° is -159.8 J/K.
Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

\Delta G^{0} at 181.0 ^{0}\textrm{C} is -723.3 kJ/mol.

Explanation:

We know, \Delta G^{0}=\Delta H^{0}-T\Delta S^{0}

where, T is temperature in kelvin.

Let's assume \Delta H^{0} and \Delta S^{0} does not change in the temperature range 25.0 ^{0}\textrm{C}  - 181.0 ^{0}\textrm{C}.

181.0^{0}\textrm{C} = (273+181.0) K = 454.0 K

Hence, at 181.0 ^{0}\textrm{C}, \Delta G^{0}=(-795.8kJ/mol)-[(454.0 K)\times (-159.8\times 10^{-3}kJ/K.mol)]

        = -723.3 kJ/mol

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Answer:

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2. The reaction will proceed forward, shifting the equilibrium position to the right.

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Formed bonds: N-H and N-N bonds

You also have to take note of the molar coefficients

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At a certain temperature, the solubility of n2 gas in water at 3.08 atm is 72.5 mg of n2 gas/100 g water . calculate the solubil
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According to Henry's law, solubility of solution is directly proportional to partial pressure thus,

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Putting the values in equation:

\frac{0.725}{3.08}=\frac{S_{2}}{8}

On rearranging,

S_{2}=\frac{0.725\times 8}{3.08}=1.88

Therefore, solubility will be 1.88 mg of N_{2} gas in 1 g of water or, 188 mg of tex]N_{2}[/tex] gas in 100 g of water.

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Explanation:

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Given pressure in mmHg = ?

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