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const2013 [10]
3 years ago
11

The value of ΔG° at 181.0 °C for the formation of calcium chloride from calcium metal and chlorine gas is ________ kJ/mol. At 25

.0 °C for this reaction, ΔH° is -795.8 kJ/mol, ΔG° is -748.1 kJ/mol, and ΔS° is -159.8 J/K.
Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

\Delta G^{0} at 181.0 ^{0}\textrm{C} is -723.3 kJ/mol.

Explanation:

We know, \Delta G^{0}=\Delta H^{0}-T\Delta S^{0}

where, T is temperature in kelvin.

Let's assume \Delta H^{0} and \Delta S^{0} does not change in the temperature range 25.0 ^{0}\textrm{C}  - 181.0 ^{0}\textrm{C}.

181.0^{0}\textrm{C} = (273+181.0) K = 454.0 K

Hence, at 181.0 ^{0}\textrm{C}, \Delta G^{0}=(-795.8kJ/mol)-[(454.0 K)\times (-159.8\times 10^{-3}kJ/K.mol)]

        = -723.3 kJ/mol

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