The ability for a substance to dissolve is affected by both temperature and pressure. Temperature As the temperature increases,
the solubility of a solid solute also increases, as the solvent can hold more of the solute particles. However, as the temperature increases for a gas, the solubility decreases. As the temperature increases, the gas molecules have more energy and are able to escape the solvent, causing the solubility to decrease. Pressure As the pressure increases on a solution containing a gaseous solute, the solubility of the gas increases. At higher pressures, there are more gas molecules above the solution, which are able to enter and dissolve into the solution. How much KNO3 can dissolve in 50 g of water at 10°C?
1 answer:
Answer:
10 g of KNO3
Explanation:
The maximum amount of KNO3 dissolve in water at different temperature, is showed in the attached graph. from this graph we can see that when the water temperature is 10 °C, the maximum amount of KNO3 in solution is 20g/ 100g H2O, in this case we have 50g H2O. so
maximum amount= (20g KNO3 / 100gH2O) * 50g H2O = 10 g KNO3
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The specific heat of a material is 0.137 J/g°C.
<u>Explanation:</u>
The specific heat formula relates the heat energy required to perform a certain reaction with the mass of the reactants, specific heat and the change in temperature during the reaction.
Q = mcΔT
Here m is the mass, Q is the heat energy required, ΔT is the change in temperature and c is the specific heat.
So, if we have to determine the specific heat of the object, then we have to determine the ratio of heat required to mass of the object with change in time, as shown below.
As mass of the object m is given as 35 g and the energy is said to be absorbed so Q = 96 J.
The temperature values given should be changed from kelvin to celsius first. So, initial temperature 293 K will become 293-273.15 = 19.85°C.
Similarly, the final temperature will be 313 - 273.15 = 39.85°C.
Then, ΔT = 39.85-19.85 = 20 °C
Then,
So, the specific heat of a material is 0.137 J/g°C.