Step-by-step explanation:
Actual graph for this problem is attached below
m∠TUV = 167°
m∠TUL = (x + 11)°
m∠LUV = (11x)°
m∠TUV=
m∠TUL+
m∠LUV
now plug in the angles for each
m∠TUV=
m∠TUL+
m∠LUV

solve the equation for x

Subtract 11 from both sides

divide both sides by 12
x=13
m∠TUL = (x + 11)°
m∠TUL = (13+ 11)°
= (24)°
answer:
24°
I believe it is D, because if you divide 2/6 its .333 minus 1.25/6, which is .124.
I=k/d^2
4=k/d^2 and 1=k/64 so if we divide the first by the second we get:
4/1=(k/d^2)/(k/64)
4=(k/d^2)*(64/k)
4=64/d^2
d^2=64/4
d^2=16
d=4 meters
Answer:
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Step-by-step explanation: