PART A:
The table of h(t) and g(t) for the value of x between 4 and 7 inclusive are shown below.
The solution for h(x)=g(x) lies between x = 4 and x = 5, this is becuase the range of value given by h(4) and h(5) and g(4) and g(5).
The graph is shown in picture 2 to confirm this. The two functions intersect each other between x = 4 and x = 5
PART B:
The point of intersection is the point where the cannon balls will collide.
<span>(1 km x 1,000m) </span>÷ 850 m/s = 1.18 s
<h3>
Answer: D. 80% of the home’s value</h3>
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Explanation:
As you probably expect, the first number 80 refers to the percentage the first loan covers. If the house is say $100,000, then the first loan is $80,000 while the second loan is the remaining $20,000.
An 80/20 mortgage, or similar, will have two monthly payments because you are getting two mortgages bundled together. Usually you should pay a down payment, though it may likely depend on your credit history. Those with good credit will pay less or no down payment, compared to those with worse credit will have to pay more down payment. A good rule of thumb is that 20% of the home's value is made as down payment, though this isn't what the "20" in "80/20" is referring to.
An 80% down payment is extremely high and unreasonable. Not many people have that kind of money laying around. A similar story applies to a 20% interest rate which is incredibly large for a mortgage rate (typically they are in the single digits such as 3%).
Answer:
25 meters
Step-by-step explanation:
Since it is a rectangle, the formula of the perimeter will be 2w+2l.
35(2)+2(x)=120.
2x=50
x=25
Answer:
We accept H₀ with the information we have, we can say level of ozone is under the major limit
Step-by-step explanation:
Normal Distribution
population mean = μ₀ = 7.5 ppm
Sample size n = 16 df = n - 1 df = 15
Sample mean = μ = 7.8 ppm
Sample standard deviation = s = 0.8
We want to find out if ozono level, is above normal level that is bigger than 7.5
1.- Hypothesis Test
null hypothesis H₀ μ₀ = 7.5
alternative hypothesis Hₐ μ₀ > 7.5
2.-Significance level α = 0.01 we will develop one tail-test (right)
then for df = 15 and α = 0,01 from t -student table we get
t(c) = 2.624
3.-Compute t(s)
t(s) = ( μ - μ₀ ) / s /√n ⇒ t(s) = ( 7.8 - 7.5 )*4/0.8
t(s) = 0.3*4/0.8
t(s) = 1.5
4.-Compare t(s) and t(c)
t(s) < t(c) 1.5 < 2.64
Then t(s) is inside the acceptance region. We accept H₀
