Answer: C
Step-by-step explanation:
12in is 1 ft
652/12 is 54r4
so atlease 55
(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.
Answer:
The answer is 7776!
Step-by-step explanation:
Use PEMDAS
PEMDAS:
Parentheses
Exponents,
Multiplication
Division (from left to right),
Addition and
Subtraction (from left to right).
Answer:
Surface Area > 1500, since its cube
Answer:
.
Step-by-step explanation:
Start by separating this decimal number into its integer part and its fraction part:
The most challenging task here is to express 
as a proper fraction. Once that fraction is found, expressing the original number 
will be as simple as rewriting a mixed number as an improper fraction.
Let 
. 
would then represent the original number.
Note that the repeating digits appear in groups of two. Therefore, if the digits in 
are shifted to the left by two places, the repeating part will continue to match:
.
Note, that this "shifting" is as simple as multiplying the initial number by 
(same as 
raised to the power of the number of digits that needs to be shifted.)
Subtract the original number from the shifted number to eliminate the fraction part completely:
.
In other words:
.
.
Therefore, the original number would be:
.
