All categories

3 years ago

The domain of a function is? When it includes all real numbers

Mathematics

1 answer:

Ray Of Light [21]3 years ago

6 0

Domain is x values... Y is y values

You might be interested in

9 - x = 6; x = 15 6x = 24; x = 6 35 = 5x; x = 7 x + 10 = 21; x = 31 <br> which one is right

ycow [4]

Answer:

35 = 5x ; x = 7

Step-by-step explanation:

plug 7 in for x

35 = 5(7)

35 = 35

hope this helps!!!

6 0

3 years ago

Read 2 more answers

Solve −3x2 + 30x − 90 = 0. x equals 5 plus or minus 2i square root of 5 x equals 5 plus or minus i square root of 5 x equals 10

Tcecarenko [31]

The x in your equation is 16/5 or 3 1/5 or 3.2 if you want it simplified

5 0

2 years ago

Read 2 more answers

Factoring with Algebra Tiles Represent the quadratic polynomial 2x2 + x – 6 using algebra tiles and determine the equivalent fac

Nezavi [6.7K]

Answer:

Two zero pair

$f(x)=(2x-3)(x+2)$

Step-by-step explanation:

We are given the following quadratic equation:

$f(x) = 2x^2+x-6$

Since, this a quadratic equation we would have two zero pairs for this model.

Factored form of polynomial:

$f(x) = 2x^2+x-6\\f(x)=2x^2+ 4x -3x -6\\f(x)=2x(x+2)-3(x+2)\\f(x)=(2x-3)(x+2)$

is the required factored form of the given polynomial.

6 0

3 years ago

What’s the answer to this equation<br> 4x7=(__x5)+(4x2)

motikmotik

Answer:

Step-by-step explanation:

4X7 =28

4X2 =8

28-8 =20/5

5 0

2 years ago

What is the z-score of a newborn who weighs 4,000 g?.

vagabundo [1.1K]

The z-score of the considered newborn having 4,000 g weight is $\dfrac{4000 - \mu}{\sigma}$

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have

$X \sim N(\mu, \sigma)$

(X is following normal distribution with mean $\mu$ and standard deviation $\sigma$ )

then it can be converted to standard normal distribution as

$Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)$

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

$P(Z \leq z) = P(Z < z) )$

Also, know that if we look for Z = z in z tables, the p value we get is

$P(Z \leq z) = \rm p \: value$

For the considered case, the statement in the problem is missing the mean weight of the newborn and standard deviation of the data set of weights of newborn.

Thus, for them, we can consider variables in place of their actual values.

Let we have:

X = weights of newborns for some considered system (in grams)
$\mu$ = mean weight of newborns (in grams)
$\sigma$ = standard deviation of the data set of weights of newborns

Then, the z-score for X = 4000 is

$z = \dfrac{x - \mu}{\sigma} = \dfrac{4000 - \mu}{\sigma}$

Thus, the z-score of the considered newborn having 4,000 g weight is $\dfrac{4000 - \mu}{\sigma}$

Learn more about z-scores here:

brainly.com/question/13299273

3 0

2 years ago