Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Answer:
4
Step-by-step explanation:
3x^2 + 2(y-1)/x+y^2
3(4)^2 + 2(3-1)/4+3^2
3x16+2x2/4+9
48+4/13
52/13
4
Answer:
option a c d are correct
Step-by-step explanation:
7 1/4 - 2 4/5
Turn the denominator into a common denominator for both fractions:
7 5/20 - 2 16/20
To subtract easier, turn the fractions into an improper fraction:
145/20 - 56/20
Subtract the numerators:
145 - 56 = 89 ---> 89/20
Simplify (to get an answer of):
4 9/20
Add labels:
Joseph has 4 9/20 ounces of candy left
