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laila [671]
2 years ago
12

Find the minimum and maximum values for the function with the given domain interval.

Mathematics
1 answer:
AlexFokin [52]2 years ago
8 0

Step-by-step explanation:

e^(x+h) is always larger than e^x.

so the minimum function value in that interval is e⁴.

and the maximum function value in that interval is e⁶.

e⁴ = 54.59815003... ≈ 54.60

e⁶ = 403.4287935... ≈ 403.43

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Toby found a $52 wallet on tge clearance rack for 60% off. if sales tax is 6.25%, how much will he pay in total
mylen [45]

Answer: Toby will pay $34.45.

Step-by-step explanation:

I did 60% of 52 and the 6.25% of 52 and added my answers together.

7 0
3 years ago
Read 2 more answers
Jeremey performs the same operations on four values of x. He records each resulting y-value in a table, as shown below. Which eq
Anestetic [448]

Answer:

Y=4x-3

Explanation: If we look 2 = 5 We can do 4(2)= 8 -3 = 5 So that the answer and 4(4)= 16-3 = 13 so these are the Y so this is the answer!

6 0
2 years ago
10 divided by 2-(16 divided by 4) +14
ankoles [38]

Answer:

15

Step-by-step explanation:

okay so you gotta use pemdas (p = parentheses, e = exponents, m = multiplication, d = division, a = addition, s = subtraction), but for the multiplication/division and addition/subtraction parts, if  division or subtraction happens first then you must do it first rather than doing multiplication or addition first

10 / 2 -(16/4) + 14

10 / 2 -(4) + 14

5 - 4 + 14

1 + 14

15

7 0
3 years ago
Read 2 more answers
Find the equation of a line parallel to 2x-2y=-4 that passes through the<br> point (3,9).
erastovalidia [21]

The line which is parallel to 2x-2y=-4 that passes through the

point (3,9) is x-y = -6.

Given that, 2x-2y = -4 passes through the point (3,9) then we have to find the equation of a line which is parallel to the given equation of line.

Let's proceed to find the equation of the line.

The slope intercept form of a straight line is one of the most common forms used to represent the equation of a line. The slope intercept formula can be used to find the equation of a line when given the slope of the straight line and the y-intercept( the y-coordinate of the point where the line intersects the y-axis).

Using the slope-intercept formula, the equation of the line is:

y = mx + b

where,

m = the slope of the line

b = y-intercept of the line

(x, y) represent every point on the line

x and y have to be kept as the variables while applying the above formula.

2x-2y = -4

-2y = -4-2x

y = -4/-2 - 2x/-2

y = 2+x

y = x+2

On comparing with y = mx+b

m = 1 and b = 2

As the lines are parallel then the slope of other line will also be same i.e., m = 1

The point from which it is passes is (3,9)

⇒ x₁ = 3 and y₁ = 9

y-y₁ = m(x-x₁)

⇒ y-9 = 1(x-3)

⇒ y-9 = x-3

⇒ y = x-3+9

⇒ y = x+6

⇒ x-y = -6

Therefore, the line which is parallel to 2x-2y=-4 that passes through the

point (3,9) is x-y = -6.

Hence, x-y = -6 is the required answer.

Learn more in depth about similar problem at brainly.com/question/1884491

#SPJ1

7 0
1 year ago
Sebastian solved the radical equation y + 1 = but did not check his solution. (y + 1)2 = y2 + 2y + 1 = –2y – 3 y2 + 4y + 4 = 0 (
Softa [21]

Answer:

There are no true solutions to the equation.

Step-by-step explanation:

<u><em>The correct equation is</em></u>

y+1=\sqrt{-2y-3}

Solve for y

squared both sides

(y+1)^2=(-2y-3)

(y^2+2y+1)=(-2y-3)

y^2+2y+1+2y+3=0

y^2+4y+4=0

(y+2)(y+2)=0

y=-2

<em>Verify</em>

substitute the value of y in the original expression

-2+1=\sqrt{-2(-2)-3}

-1=1 ----> is not true

therefore

There are no true solutions to the equation.

4 0
3 years ago
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