Answer:
Area(PART)= 7.5 u^2
Step-by-step explanation:
RT=1 unit
PA=4 units
Distance between T (or R) and PA= 3 units
RT;PA = Bases
T (or R)--> PA= Altitude/Height
Area of trapezoid= Alt(B1+B2)/2
--> 3(1+4)/2
=> 3*5÷2
=15/2
=7.5
Thanks
Answer:
2•5•2
Step-by-step explanation:
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now it let me
Answer:
Step-by-step explanation:add 4 to the side that has "13" then you will get "17" then divided -7 from x and "17"and your answer is x=idk
Answer:
i think 6x
Step-by-step explanation:
cz we have a variable
The distance travelled by an object at time t is given by: d = stwhere d is the distance, s is the speed and t is the time.
Given that the cheetah travels a maximum of 70mph, the distance travelled by the cheetah travelling at 70mph at time t is given by d = 70t
There are 60 mins in one hour, so the distance given in miles per minutes is d = 70/60t = 1.167 miles per minutes.
Part B:
Given that t = 10 minutes, the distance covered by the cheetah in 10 minutes is d = 1.167 x 10 = 11.67 miles.
Part C:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the first 8 minutes is given by
d = 1.167 x 8 = 9.33 miles.
Part D:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the second 8 minutes is given by
d = 40/60 x 8 = 5.33 miles
Part E:
The distance the cheetah traveled in the first 8 minutes more than in the second 8 minutes is given by
9.33 miles - 5.33 miles = 4 miles.
Part F:
The ratio of the distance travelled in the first 8 minutes to the distance travelled in the next minutes is given by
9.33 : 5.33 = 1.75 : 1.
Therefore, the distance traveled by the cheetah during the first 8 minutes is 1.75 times greater than the distance traveled during the second 8 minutes.