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2 years ago

Can someone please help me with this geometry question.

Mathematics

2 answers:

Scrat [10]2 years ago

8 0

W is 63 . X is 86 . Y is 38 . Z is 25

I hope this helps!

galben [10]2 years ago

6 0

To find w, you subtract 117 from 180. After that you get w = 63. Now you add 63 and 31 to get 94. You then subtract 94 from 180 to get x = 86. Now you add 86 and 56 to get 142. You then subtract 142 from 180 to get y = 38. Now you add 38 and 117 to get 155. Again you subtract 155 from 180 to get z = 25

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12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

3 0

1 year ago

What did Martina do to the equation 4x=2x + 402 to get 2x = 402

Tpy6a [65]

Step-by-step explanation:

she took the 2X and substract 4X-2X

the answer will be 2X=402

4 0

2 years ago

Is this answer correct?

disa [49]

Answer: ya

Step-by-step explanation:

5 0

2 years ago

One person can do a certain job in 15 minutes and another person can do the same job in 30 minutes. How many minutes will it tak

Flauer [41]

Hello! Your answer is B, 10 minutes.

Say the x = minutes taken to do the job. You can set up an equation like this to solve this.

$\frac{1}{15} x + \frac{1}{30} x = 1$

This is representative of the situation. The fractions each represent how much each person does in a minute, and when they're multiplied by x, that's how much of the project they get done based off of the minutes they work together on the job. Add the two together, and you get how much of the project is finished in x amount of time. Set it equal to 1, as you are looking for 100% completion.

Once you have this equation, find a common denominator, add, and solve.

$\frac{1}{15} x + \frac{1}{30} x = 1$

$\frac{2}{30} x + \frac{1}{30} x = 1$

$\frac{3}{30}x = 1$

$\frac{1}{10}x = 1$

$x = 10$

Therefore, it will take them 10 minutes to do the job together.

Hope this helps!

8 0

3 years ago

During one snowy month a kentucky school held classes 9/11 of possible the school days if there are 22 possible school days how

SOVA2 [1]

This question isn't phrased correctly, but I will assume it's asking about common denominators with fractions.

9/11 1/22

18/22 1/22

18 school days.

5 0

2 years ago