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arsen [322]
3 years ago
10

Can someone please help me with this

Mathematics
1 answer:
Archy [21]3 years ago
4 0

Step-by-step explanation:

By Exterior Angle theorem,

(5y + 3)° + (4y + 8)° = 146°

=> 9y + 11 = 146

=> y = 15.

Hence Angle ABC = (4y + 8) = [4(15) + 8]° = 68°.

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slava [35]

The geometrical relationships between the straight lines AB and CD is that they are parallel to each other

<h3>How to determine the relationship</h3>

It is important to note the following;

  • A drawn from the origin and passes through point A (a , b), then the equation of OA = ax + by
  • If a line is drawn from the origin and passes through point B (c , d), then the equation of OB = cx + dy

We  find the equation of AB by subtracting OB from OA, thus AB = (c - a)x + (d - b)y

The slope of line AB =

⇒ OA= 2 x + 9 y

⇒ OA = 4 x + 8 y

⇒AB = OB - OA

⇒AB = (4 x + 8 y) - (2 x + 9 y)

⇒ AB = 4 x + 8 y - 2 x - 9 y

Collect like terms

⇒ AB = (4 x - 2 x) + (8 y - 9 y)

⇒AB = 2 x + -y

⇒ AB = 2 x - y

⇒ Coefficient of x = 2

⇒ Coefficient of y = -1

⇒ The slope of ab = \frac{-2}{-1} = 2

For CD

⇒ CD = 4 x - 2 y

⇒Coefficient of x = -4

⇒ Coefficient of y = -2

⇒The slope of cd = \frac{-4}{-2} = 2

Note that Parallel lines have same slopes

And Slope of ab = slope of cd

AB // CD

Therefore, the geometrical relationships between the straight lines AB and CD is that they are parallel to each other

Learn more about parallel lines here:

brainly.com/question/24607467

#SPJ1

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