if there were 43 girls and 41 boys and the girls were counted as negatives and the boys are positive, how many couples will the
1 answer:
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Yeeee
assuming your equaiton is
remember some nice log rules
translates to 
and
and
and
and
and
if
then a=b
so
we can simplify a bit of stuff here
the
can be simplified to 
so we gots now
same base so
times both sides by 5
divide both sides by 2
answer is x=75
assuming your equaiton is
remember some nice log rules
and
and
and
and
and
if
so
we can simplify a bit of stuff here
the
so we gots now
same base so
times both sides by 5
divide both sides by 2
answer is x=75