In order to solve for r you have to place all the number in one side. then isolate r ...... r=1
Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
One equation for this would be

We start by finding the slope between the two points:

A line parallel to this one will have the same slope. We will use point-slope form to write our equation:
Answer:
y = 8x + 38
Step-by-step explanation:
To find the slope we set up y = mx + b and plug m (our slope) in and then plug in the point into x and y to find b (our y-intercept)
y = mx + b
y = 8x + b
6 = 8(-4) + b
6 = -32 + b
+32 +32
38 = b
So using our slope and our intercept we have our slope intercept
y = mx + b
y = 8x + 38
Hope this helps :)