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scZoUnD [109]
3 years ago
8

Micah is flying a kite and has used all of the 50 meters of the string. If the kite is 13 meters above the ground, what is the a

ngle of elevation that
the boy has when looking up at the kite?
Sketch a picture and solve. Round to the nearest degree.

ILL MARK YOU THE BRANLIEST ANSWER IF YOU ANSWER FAST PLEASE
Mathematics
1 answer:
Inessa05 [86]3 years ago
3 0

Answer:

37

Step-by-step explanation:

I believe you subtract the meters to the meters above the ground

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46.The function f graphed above is the function f(x) = log2(x) + 2 for x > 0. Find a formula for the inverse of this function
pantera1 [17]

Answer:

The inverse for log₂(x) + 2  is - log₂x + 2.

Step-by-step explanation:

Given that

f(x) = log₂(x) + 2

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f(x) = log₂(x) + 2

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As we know that

log₂(a/b) = log₂a - log₂b

g(x) = log₂1 - log₂x + 2

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3 0
4 years ago
which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l
victus00 [196]
One equation for this would be

y = \frac{41}{16} x-\frac{55}{8}

We start by finding the slope between the two points:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}
\\
\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})
\\
\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})
\\
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A line parallel to this one will have the same slope.  We will use point-slope form to write our equation:

y-y_1=m(x-x_1)
\\
\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})
\\
\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}
\\
\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}
\\
\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}
\\
\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}
\\
\\y=\frac{41}{16}x-\frac{550}{80}
\\
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6 0
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kompoz [17]

Answer:

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Step-by-step explanation:

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+32   +32

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So using our slope and our intercept we have our slope intercept

y = mx + b

y = 8x + 38

Hope this helps :)

7 0
3 years ago
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