Narrowing it down it's either a or c because the other 2 choices open downward (negative a).
Graphing the 2 parabolas choice c is narrower.
c
Answer:
How many general admission tickets were purchased? __<u>136</u>__
How many upper reserved tickets we purchased? _<u>300</u>_
Step-by-step explanation:
Let the number of general tickets = g.
Let the number of reserved tickets = r.
6.5g + 8r = 3284
g + r = 436
6.5g + 8r = 3284
(+) -8g + -8r = -3488
--------------------------------
-1.5g = -204
g = 136
g + r = 436
136 + r = 436
r = 300
Answer:
How many general admission tickets were purchased? __<u>136</u>__
How many upper reserved tickets we purchased? _<u>300</u>_
Answer:
Total number of possible combinations are 6
Length width
23 dm 2m
21 dm 4 dm
19 dm 6 dm
17 dm 8 dm
15 dm 10 dm
13 dm 12 dm
Step-by-step explanation:
We are given that
Perimeter of rectangular garden=50 dm
Width is even number.
Length is always longer than or equal to width.
Let length of rectangular garden=x
Width of rectangular garden=y
We have to find the possible number of combinations .
Perimeter of rectangular garden=



If y=2 dm
x=25-2=23 dm
If y=4 dm
x=25-4=21 dm
If y=6 dm
x=25-6=19 dm
If y=8 dm
x=25-8=17 dm
If y=10 dm
x=25-10=15 dm
If y=12 dm
x=25-12=13 dm
If y=14 dm
x=25-14=11 dm
x<y
It is not possible
Then, possible combinations are 6
Length width
23 dm 2m
21 dm 4 dm
19 dm 6 dm
17 dm 8 dm
15 dm 10 dm
13 dm 12 dm