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Morgarella [4.7K]
3 years ago
5

I need to find the answer to 2/3 - 1/5. What is it?

Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0
2/3 - 1/5

make a common denominator

10/15 - 3/15

simplify

7/15 is your answer

hope this helps
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Vladimir [108]

105 i think nvm not corrupted picture

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3 years ago
Type your answer and then click or tap Done.
masya89 [10]

Answer:

See below

Step-by-step explanation:

x(x-2y)-(y-x)2  

Final result :

-y2

Step by step solution :

Step  1  :

Equation at the end of step  1  :

x • (x - 2y) -  (y - x)2

Step  2  :

2.1     Evaluate :  (y-x)2   =    y2-2xy+x2  

Final result :

-y2

7 0
2 years ago
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Answer:

C :) hope it helps

Step-by-step explanation:

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3 years ago
Reggie has a rectangular piece of paper that is 12 inches long and 7 inches wide. He is going to cut the paper from corner to co
neonofarm [45]

A property from geometry states that rectangles have congruent opposite sides. Thus, no matter which diagonal Reggie cuts, it still has the same lengths. Since it's a rectangle and we cut from corner to corner, we create a right triangle. See the picture below:

<u>___________12 inches_______</u>

7 |

i |

n |

Because it's a rectangle, it won't matter which corner we cut. But if we fold at the cut lines, we would make an in the rectangle's center.

The cut line and two sides make a right triangle. One leg is 12, one leg is 7, and we need to find the third side. The Pythagorean Theorem - sum of the squares of the legs equals the square of the hypotenuse - is applied.

Let S = the length of the side from corner to corner

S² = 12² + 7²

S² = 144 + 49

S² = 193

S = √193 or -√193

Because we are dealing with lengths, we only want positive numbers. -√193 is not used. Thus S = √193

S = √193 = 13.8924439894

S = 18.92 (rounded to two places)


Thus, Reggie will cut 18.92 inches of paper.

5 0
3 years ago
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

5 0
3 years ago
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