Answer:
a) 25.15
b)
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c) (x,y) = (1, -2pi)
Step-by-step explanation:
a)
First lets calculate the velocity, that is, the derivative of c(t) with respect to t:
v(t) = (-sin(t), cos(t), 2t)
The velocity at t0=4pi is:
v(4pi) = (0, 1, 8pi)
And the speed will be:
s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15
b)
The tangent line to c(t) at t0 = 4pi has the parametric form:
(x,y,z) = c(4pi) + t*v(4pi)
Since
c(4pi) = (1, 0, (4pi)^2)
The tangent curve has the following components:
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c)
The intersection with the xy plane will occurr when z = 0
This happens at:
t1 = -2pi
Therefore, the intersection will occur at:
(x,y) = (1, -2pi)
In fact, both Amanda's and Stephen's profs are correct; they are just using different supplementary angles. Amanda's is using the supplementary angles <span>∠1 and ∠4, and</span> ∠3 and ∠4, whereas Stephen is using ∠1 and ∠2, and <span>∠2 and ∠3.</span><span> </span>Please check the picture to visualize this more effectively.
Answer:
b. y= -4(x-3)^2+4
Step-by-step explanation:
BECAUSE I DID THIS BEFORE AND THE TEACHA TOLD ME THE RIGHT ANSWER! ITS CORRECT TRUST MEEEE
IM SERIOUS! >:0
<u><em>FR THOO</em></u>
The addition of +7 influences the y values of the graph. Since it is positive, the graph of y=IxI would be moved 7 units upwards.
Hope I helped :)
Do you need the fraction? I don’t understand what you are asking