You duckkersndnd d did d sksbdkdbskdbskdvsksvskdyfnrvakchrbakrbsksvrkd
Answer:
59 to 66
Step-by-step explanation:
Mean test scores = u = 74.2
Standard Deviation =
= 9.6
According to the given data, following is the range of grades:
Grade A: 85% to 100%
Grade B: 55% to 85%
Grade C: 19% to 55%
Grade D: 6% to 19%
Grade F: 0% to 6%
So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.
6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)
The formula for z score is:

For z = -1.56, we get:

For z = -0.88, we get:

Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)
Answer:
Natural Numbers are basically "counting numbers". If I ask you to start counting, you'll start at 1, then 2, then 3, and so on. It doesn't include 0 or any negative numbers because you wouldn't start from -10 when asked to count.
<h3>
brainliest is appreciated :)</h3>
Answer:
You have to solve for the letter
Step-by-step explanation:
For example, Q5 is 40 - 5n = -2.
- You subtract 40 from -2 and get -42 then you have 5n = -42.
- You divide 5 to -42 so
. - The answer is -8.4.
*Use a calculator if necessary.*
~Hope this is helps (.^.)~