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lys-0071 [83]
2 years ago
8

le" class="latex-formula">
Mathematics
2 answers:
Dmitry_Shevchenko [17]2 years ago
6 0
He right from step to step
vichka [17]2 years ago
5 0

Answer:

{p}^{4} x

Step-by-step explanation:

1) Regroup terms.

{p}^{2} p^{2} x

2) Use product rule.

{p}^{2 + 2} x

3) Simplify 2 × 2 to 4.

p ^{4} x

Therefor, the answer is p⁴x

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Chad is driving 56 miles per hour. Chad drove 168 miles in 3 hours.Chad will drive 672 more miles. He continues to drive at the
shusha [124]
So, 672 miles divided by 56 miles per hour = 12 hours
6 0
3 years ago
Can someone please help me
Airida [17]

Step-by-step explanation:

it is a simple addition and subtraction sequence :

10 + 0 + -21 + 14 = 3

since the result is positive, it is overall a gain.

if the result were negative, it would be an overall loss.

so, he had an overall gain of 3 yards.

5 0
2 years ago
-4x - 10x<br> Combine Like Terms
kondaur [170]

Answer:

-14x

Step-by-step explanation:

-4x+-10x =-14x

5 0
3 years ago
Read 2 more answers
Given f(x)=1/x+5 and g(x)=x-2
vladimir1956 [14]

For this case we have the following functions:

f (x) = \frac {1} {x + 5}\\g (x) = x-2

We must find f (g (x)). So:

f (g (x)) = \frac {1} {(x-2) +5} = \frac {1} {x-2 + 5} = \frac {1} {x + 3}

Finally we have to:

f (g (x)) = \frac {1} {x + 3}

For the function to be defined the denominator must be different from 0. That is x different from -3.

Answer:

Option B

3 0
3 years ago
A person invest $1200 in an account that earns 2% interest compound quarterly. Find when the value of the investment reaches $15
Basile [38]

Answer:

After 11 years the value of the investment reaches $1500.00

.

Step-by-step explanation:

The formula used for finding time (when the value reaches certain amount) is:

A= P(1+\frac{r}{n})^{nt}

where A= Future VAlue

P= Principal Value

r= rate of interest (in decimal)

n= no of times investment is compounded

t= time

Putting the values given and finding Time t,

A= $1500

P= $1200

r= 2% or 0.02

n= 4 (compound quarterly)

A= P(1+\frac{r}{n})^{nt}

1500= 1200(1+\frac{0.02}{4})^{4t}

Dividing both sides by 1200 and solving 0.02/4 = 0.005

1.25= (1+0.005)^{4t}

1.25= (1.005)^{4t}

Since t is in power we take the logarithm ln on both sides.

The rule of logarithm says that the exponent can be multiplied with the base when taking log

\ln1.25=ln( 1.005)^{4t}\\\ln1.25=4t * ln( 1.005)\\0.22 = 4t * 0.005\\Solving\,\,\\\frac{0.22}{4*0.005} = t\\=> t= 11\, years

8 0
3 years ago
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