Answer:
EF = 8.8 cm
Step-by-step explanation:
In the given right angled ΔDEF, DE is the hypotenuse while EF and DF are adjacent sides. So that applying the Pythagoras theorem, we have;
= 
+ 
= 
+ 
= + 
262.44 = + 184.96
= 262.44 - 184.96
= 77.48
EF = 
= 8.8023
EF = 8.8 cm
The length of side EF is 8.8 cm.
7) Area trapezoid = (B+b).H/2, but the Median is equal to (B+b)./ 2
84 =12 . H ==> H = 84/12 ==> H = 7
11) Area Equilateral triangle inscribe in a cercle with Radius R = 2√3
Area = (B.. Altitude) / 2. Calculate H, the altitude. The altitude in an equilateral triangle bisects the opposite side. Apply Pythagoras
(2√3)² = (√3)² + H² ==> 12 = 3 + H² ==> H² = 9 & H = 3
Hence Are = (2√3 x 3) /2 ==> 3√3 unit² or 5.2 unit²
12) Area of regular hexagone with perimeter =12
regular hexagone is formed with 6 equilateral triangles with
each side =12/6 = 2 units
Let's calculate the area of 1 equilateral triangle. Follow the same logic as in problem 11 & you will find that Altitude = √3, Area =(2.√3)/2 =√3 =1.73 Unit³
13) a) Circumference of a circle : 2πR==> 2π(30) =60π = 188.4
b) Area of a circle =πR³ ==> π(30)² = 900π = 2,826 unit²
This would be the Transitive Property of Congruence.
This property of congruence states that if two angles/segments/polygons are both congruent to something else, then they are congruent to each other.
Hope this helps! :)
Answer:
Step-by-step explanation:
In order to find the answer to this question you need to find the rule then apply that rule in till you find the 10th term of the sequence.
Rule = ×2
Hope this helps
