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3 years ago

Determine the 10th term of the sequence 3, 6, 12,

Mathematics

1 answer:

Charra [1.4K]3 years ago

4 0

Answer:

$1536$

Step-by-step explanation:

In order to find the answer to this question you need to find the rule then apply that rule in till you find the 10th term of the sequence.

Rule = ×2

$3\times2=6\times2=12\times2=24\times2=48\times2=96\times2=192\times2=384\times2=768\times2=1536$

$=1536$

Hope this helps

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How to solve for x 15 + 8x = 45 + 6x

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Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

15+8x=45+6x

Step 1: Simplify both sides of the equation.

8x+15=6x+45

Step 2: Subtract 6x from both sides.

8x+15−6x=6x+45−6x

2x+15=45

Step 3: Subtract 15 from both sides.

2x+15−15=45−15

2x=30

Step 4: Divide both sides by 2.

x=15

Answer:

x=15

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Step-by-step explanation:

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Expand the expression: 2.2(-4k + 1)

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Choose the graph that represents the following system of inequalities: y ≥ −3x + 1 y ≤ 1 over 2x + 3 In each graph, the area for

svet-max [94.6K]

Answer:

Correct graph is C

Step-by-step explanation:

Given two inequalities are:

1. $y\leq -3x+1$

2. $y\leq x+3$

Step1 : Remove the inequalities

1. $y=-3x+1$

2. $y=x+3$

Step2 : Finding intersection points of equations

By solving linear equation

$y=-3x+1=x+3$

$-3x+x+3$

$x=-0.5$

Replacing value of x in any equations

we get,

$y=x+3\\$

$y=-0.5+3$

$y=2.5$

Therefore, Point of intersection is (-0.5,2.5)

Step3: Test of origin (0,0)

Here, If inequalities holds true for origin then, shades the graph towards the origin.

For equation 1.

$y\leq -3x+1$

$0\leq -3(0)+1$

$0\leq +1$

True, Shade graph towards origin.

For equation 2.

$y\leq x+3$

$0\leq 0+3$

$0\leq 3$

True, Shade graph towards origin.

Thus, Correct graph is C

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