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patriot [66]
3 years ago
13

Peter bought 12.4 gallons of gas at $2.76 per gallon. How much money did Peter spend?

Mathematics
2 answers:
Dafna11 [192]3 years ago
8 0
Peter spent $34.22
2.76(12.4)=34.224
zheka24 [161]3 years ago
3 0
4.49 dollars was how much peter spent in total
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Simplify the expression 3a + b, when a=1.4 -2x and b=-0.2x + 1.7*
kenny6666 [7]

Answer:5.9-6.2x

Step-by-step explanation:

a=1.4-2x

b=-0.2x+1.7

 3a+b

=3(1.4-2x)+(-0.2x+1.7)

=4.2-6x-0.2x+1.7

=4.2+1.7-6x-0.2x

=5.9-6.2x

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A letter that represents an unknown number is
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Hey there! Hello!

I believe what this question (more of a statement) is asking is to identify what a letter that represents an unknown number is called. Most of the time, i refer to it as just a variable, or an unknown variable. It can also be referred to as just an unknown value. 

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What is the area of a kite in the figure below?
Leto [7]

Answer:

The are is 1,200 cm squared

Step-by-step explanation:

10 * 20 = 200

20 * 50 = 1000

1000 + 200 = <em><u>1,200cm squared</u></em>

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3 years ago
Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is running, he goes from 70
kumpel [21]

Answer:

His acceleration is \frac{1}{15} meters per seconds²

Step-by-step explanation:

Acceleration is the rate of change of the speed

The formula of acceleration is a=\frac{v_{f}-v_{i}}{t} , where

  • v_{f} is the final speed
  • v_{i} is the initial speed
  • The unit of the acceleration is meters/second²

∵ Jim goes from 70 meters/minute (beginning speed) to

   106 meters/minute (final speed) in 9 seconds

∴ His initial speed v_{i} = 70 meters/minute

- Change it the meter per second

∵ 1 minute = 60 seconds

∴ \frac{70}{(1)(60)}=\frac{70}{60}=\frac{7}{6}  meters/second

∴ v_{i} = \frac{7}{6}  meters/second

∵ His final speed v_{f} = 106 meters/minute

- Change it the meter per second

∴ \frac{106}{(1)(60)}=\frac{106}{60}=\frac{53}{30}  meters/second

∴ v_{f} = \frac{53}{30}  meters/second

∵ The time of the change of his speed is 9 seconds

∴ t = 9

∵ The formula of acceleration is a=\frac{v_{f}-v_{i}}{t}

- Substitute the values of t, v_{i}  and v_{f} in the formula above

∴  a=\frac{\frac{53}{30}-\frac{7}{6}}{9}=\frac{1}{15}

∴ His acceleration is \frac{1}{15} meters per seconds²

3 0
3 years ago
A chemist has two alloys, one of which is 15% gold and 20% lead and the other which is 30% gold and 50% lead. How many grams of
vlabodo [156]

Answer: 490 grams of the first alloy should be used.

30 grams of the second alloy should be used.

Step-by-step explanation:

Let x represent the weight of the first alloy in grams that should be used.

Let y represent the weight of the second alloy in grams that should be used.

A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is

0.15x and 0.2x

The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is

0.3y and 0.5y

If the alloy to be made contains 82.5 g of gold, it means that

0.15x + 0.3y = 82.5 - - - - - - - - - - - -1

The second alloy would also contain 113 g of lead. This means that

0.2x + 0.5y = 113 - - - - - - - - - - - - -2

Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes

0.03x + 0.06y = 16.5

0.03x + 0.075y = 16.95

Subtracting, it becomes

- 0.015y = - 0.45

y = - 0.45/- 0.015

y = 30

Substituting y = 30 into equation 1, it becomes

0.15x + 0.3 × 30 = 82.5

0.15x + 9 = 82.5

0.15x = 82.5 - 9 = 73.5

x = 73.5/0.15

x = 490

6 0
3 years ago
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