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jeka94
3 years ago
12

a large bag of marbles contains equal amounts of 5 colors (red, orange, yellow, green, and Blue). Joaquin selects 1 marble then

puts it back and selects another. find the probability of him selecting a yellow marble both times
Mathematics
2 answers:
Bumek [7]3 years ago
7 0
The answer to this question is 5/25 five out of twenty five will be yellow.  
denpristay [2]3 years ago
7 0

Answer:  The required probability is 4%.

Step-by-step explanation:  Given that a large bag of marbles contains equal amounts of 5 colors, red, orange, yellow, green, and blue. Joaquin selects 1 marble then puts it back and selects another.

We are to find the probability of selecting a yellow marble both times.

Let x number of marbles of each color is present in the bag.

Let S be the sample space for the experiment of selecting a marble from the bag.

n(S) = x + x + x + x + x = 5x.

Now, let A denote the event of selecting a yellow marble.

Then, n(A) = x.

Since the second marble is drawn after replacing the first one, so the probability of selecting a yellow marble both times is given by

P=\dfrac{n(A)}{n(S)}\times \dfrac{n(A)}{n(S)}=\dfrac{x}{5x}\times\dfrac{x}{5x}=\dfrac{1}{25}=\dfrac{1}{25}\times 100\%=4\%.

Thus, the required probability is 4%.

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The fraction is 1/4 and the two square roots of 0.25 is 1/2 or 0.5. I hope this helped
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A town in east Texas received 10 inches of rain in 2 weeks. If it kept raining at this rate for a 31- day month, how much rain d
umka21 [38]

2 weeks = 14 days

10 / 14 = 0.71428571428

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The town received about 22 inches of rain.

If you include the 2 weeks, then it would be 32 inches of rain.


Hope this helps!

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3 years ago
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jeyben [28]

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The scale factor is 1/4

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5 0
3 years ago
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5 0
4 years ago
The Aluminum Association reports that the average American uses 56.8 pounds of aluminum in a year. A random sample of 50 househo
nalin [4]

Answer:

\mu = 56.8

\sigma = 12.1

A)what is the probability that the sample mean will be More than 58 pounds

P(x>58)

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{58-56.8}{12.1}

Z=0.09917

refer the z table

P(x<58)=0.5359

P(X>58)=1-P(x<58)=1-0.5359=0.4641

Hence the probability that the sample mean will be More than 58 pounds is 0.4641

B)what is the probability that the sample mean will be More than 57 pounds

P(x>57)

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{57-56.8}{12.1}

Z=0.0165

refer the z table

P(x<57)=0.5040

P(X>57)=1-P(x<57)=1-0.5040=0.496

Hence the probability that the sample mean will be More than 57 pounds is 0.496

C)what is the probability that the sample mean will be Between 55 and 57 pound

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{57-56.8}{12.1}

Z=0.0165

refer the z table

P(x<57)=0.5040

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{55-56.8}{12.1}

Z=-0.1487

refer the z table

P(x<55)=0.4443

P(55<x<57)=P9x<57)-P(x<55) =0.5040-0.4443=0.0597

Hence the probability that the sample mean will be Between 55 and 57 pounds is 0.0597

D)what is the probability that the sample mean will be Less than 53 pounds

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{53-56.8}{12.1}

Z=−0.314

refer the z table

P(x<53)=0.3783

The probability that the sample mean will be Less than 53 pounds is 0.3783

E)what is the probability that the sample mean will be Less than 48 pounds

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{48-56.8}{12.1}

Z=−0.727

refer the z table

P(x<48)=0.2358

The probability that the sample mean will be Less than 48 pounds is 0.2358

5 0
3 years ago
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