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3 years ago

What is the solution to the following system? -4y=8 x+3y-3z=-26 2x-5y+z=19

Mathematics

2 answers:

Kisachek [45]3 years ago

8 0

Answer:

x=1 y=-2 z=7

Step-by-step explanation:

took the quiz edg 2020

Viktor [21]3 years ago

3 0

⓵
-4ỿ = 8

Simplify the left side in order to isolate the ỿ!

-4ỿ = 8
+4 +4

Ỿ = 12

⓶
× + 3y - 3z = -26

Simplify the left side in order to isolate the ×, ỿ and z!

× + 3y - 3z = -26
÷3 ÷3

× + ỿ - 3z = -8,66 periodic
÷-3 ÷-3

× + ỿ + z = 2,88 periodic

⓷
2× - 5ỿ + z = 19

Simplify the left side in order to isolate the ×, ỿ and z!

2× - 5ỿ + z = 19
÷2 ÷2

× - 5ỿ + z = 9,5
÷-5 ÷-5

× + ỿ + z = -1,9

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3 years ago

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3 years ago

Use cubic regression to find a function that fits the following points.

olasank [31]

Answer:

The cubic regression that fits the points $(x,y) =(-2,-16)$ , $(x,y) = (1,5)$ , $(x,y) = (3, 59)$ and $(x,y) =(6,440)$ is $y =2\cdot x^{3}+x+2$ .

Step-by-step explanation:

A cubic polynomial is a polynomial that has the following form:

$y = a\cdot x^{3}+b\cdot x^{2}+c\cdot x + d$ (1)

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$a$ , $b$ , $c$ , $d$ - Coefficients, dimensionless.

We construct the following system of equations to determine the coefficients of the cubic regression:

$(x,y) =(-2,-16)$

$-8\cdot a +4\cdot b -2\cdot c + d = -16$ (1)

$(x,y) = (1,5)$

$a+b+c+d= 5$ (2)

$(x,y) = (3, 59)$

$27\cdot a + 9\cdot b + 3\cdot c + d = 59$ (3)

$(x,y) =(6,440)$

$216\cdot a + 36\cdot b + 6\cdot c + d = 440$ (4)

The solution of the system of linear equations is:

$a = 2$ , $b = 0$ , $c = 1$ , $d = 2$

The cubic regression that fits the points $(x,y) =(-2,-16)$ , $(x,y) = (1,5)$ , $(x,y) = (3, 59)$ and $(x,y) =(6,440)$ is $y =2\cdot x^{3}+x+2$ .

7 0

3 years ago

Pn=1/3pn-1 and p4=108 , then p6= ? please show steps

Natali5045456 [20]

$p_n=\dfrac13p_{n-1}$
$\implies p_n=\dfrac13\left(\dfrac13p_{n-2}\right)=\dfrac1{3^2}p_{n-2}$
$\implies p_n=\dfrac13\left(\dfrac13p_{n-3}\right)=\dfrac1{3^3}p_{n-3}$

and so on, up to

$p_n=\dfrac1{3^{n-4}}p_4=\dfrac{108}{3^{n-4}}$

which means

$p_6=\dfrac{108}{3^{6-4}}=\dfrac{108}9=12$

6 0

3 years ago