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3 years ago

12

What is the solution to the following system? -4y=8 x+3y-3z=-26 2x-5y+z=19

2 answers:

Kisachek [45]3 years ago

8 0

Answer:

x=1 y=-2 z=7

Step-by-step explanation:

took the quiz edg 2020

Viktor [21]3 years ago

3 0

⓵
-4ỿ = 8

Simplify the left side in order to isolate the ỿ!

-4ỿ = 8
+4 +4

Ỿ = 12

⓶
× + 3y - 3z = -26

Simplify the left side in order to isolate the ×, ỿ and z!

× + 3y - 3z = -26
÷3 ÷3

× + ỿ - 3z = -8,66 periodic
÷-3 ÷-3

× + ỿ + z = 2,88 periodic

⓷
2× - 5ỿ + z = 19

Simplify the left side in order to isolate the ×, ỿ and z!

2× - 5ỿ + z = 19
÷2 ÷2

× - 5ỿ + z = 9,5
÷-5 ÷-5

× + ỿ + z = -1,9

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8 grams = milligrams

Digiron [165]

Answer:

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3 years ago

Read 2 more answers

Please help and explain with these 2 math questions!!!!!!

Volgvan

1) -10x+y=4

Now, you should substitute x in every situation.

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3 years ago

Selma's class is making care packages to give to victims of a natural disaster. Selma packs one box in 5 minutes and has already

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3 years ago

Read 2 more answers

1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.

iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is $53.13\°$

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Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

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The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

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$x=arcsin(\frac{16}{20})=53.13\°$

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The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

$SA=b^{2}+4[\frac{1}{2}(b)(h)]$

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

$h=b/2$ -------> by an 45° angle

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$b=2h$

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