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mel-nik [20]
3 years ago
11

What is, 3 to the power of 2, times, 3 to the power of 5.

Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0

Answer:

3^7

Step-by-step explanation:

3^2 * 3^5

a^b * a^c, since the bases are the same, we can add the exponents

a^ ( b+c)

3^(2+5)

3^7

You might be interested in
What is the length of segment AB with point A and B located at (-4, 1) and (2, 9)
navik [9.2K]

Answer:

<h3>The answer is 10 units</h3>

Step-by-step explanation:

The distance between two points or a line segment can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4, 1) and (2, 9)

The length of segment AB is

|AB|  =  \sqrt{ ({ - 4 - 2})^{2}  +  ({1 - 9})^{2} }  \\  =  \sqrt{( { - 6})^{2}  +   ({ - 8})^{2} }  \\  =  \sqrt{36 + 64}  \\  =  \sqrt{100}  \:  \:  \:  \:  \:  \:  \:  \:  \\  = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>10 units</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
Hi can some1 help quickly :) tysm
frez [133]

Answer:

1:2 is the simplest form

Step-by-step explanation:

the ratio is 4:2 but since That's not the simplest form, you must find the GCF. the GCF is 2, divide both numbers by 2 and you get 2:1. you pull the ratio from segment AB and segment DF since both of them have measurements already stated.

hope this helps! :)

8 0
3 years ago
Avery has $3. She earns $1.20 for each chore she does. (She can complete fractions of
Sonja [21]

Answer:

She would have to do a chore 11.25 times

Step-by-step explanation:

well first you would divide 1.20 by 13.50 and get 11.25 and then add the $3 to it and get 14.25 and that would be enough money for the game  

please mark brainliest

5 0
3 years ago
For the feasibility region shown below, find the maximum value of the function P=2x+3y.
timofeeve [1]
Corner points in this graph are: ( 0,0 ) ( 0,8 ) ( 5,6 ) and ( 8, 0 ).
If we plug those values in : P = 2 x + 3 y
P ( 0,0 )= 0
P ( 0,8 ) = 2 * 0 + 3 * 8 = 24
P ( 6 , 5 ) = 2 * 6 + 3 * 5 = 12 + 15 = 27
P ( 8 , 0 ) =  2 * 8 + 3 * 0 = 16
The maximum value is:
P max ( 6 , 5 ) = 27
3 0
3 years ago
Read 2 more answers
Suppose that the length of a side of a cube X is uniformly distributed in the interval 9
Nastasia [14]

Answer:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

Step-by-step explanation:

Given

9 < x < 10 --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

v = x^3

For a uniform distribution, we have:

x \to U(a,b)

and

f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.

9 < x < 10 implies that:

(a,b) = (9,10)

So, we have:

f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Solve

f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Recall that:

v = x^3

Make x the subject

x = v^\frac{1}{3}

So, the cumulative density is:

F(x) = P(x < v^\frac{1}{3})

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right. becomes

f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.

The CDF is:

F(x) = \int\limits^{v^\frac{1}{3}}_9 1\  dx

Integrate

F(x) = [v]\limits^{v^\frac{1}{3}}_9

Expand

F(x) = v^\frac{1}{3} - 9

The density function of the volume F(v) is:

F(v) = F'(x)

Differentiate F(x) to give:

F(x) = v^\frac{1}{3} - 9

F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}

F'(x) = \frac{1}{3}v^{-\frac{2}{3}}

F(v) = \frac{1}{3}v^{-\frac{2}{3}}

So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

8 0
3 years ago
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