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r-ruslan [8.4K]
3 years ago
9

 PLEASE HELP!! A tennis ball machine serves a ball vertically into the air from a height of two feet, with an initial speed of 1

20 feet per second. After how many seconds does the ball attain its maximum height? Round to the nearest whole foot
Mathematics
2 answers:
a_sh-v [17]3 years ago
5 0

Answer:

After 3.73 seconds ball will achieve the maximum height.

Step-by-step explanation:

Initial speed of the tennis ball is u = 120 feet per second

Since at the maximum height ball's final speed will be = 0

So we will apply the formula of motion against gravitational pull

v = u - gt

Where v = speed of the ball at maximum height

u = initial speed

g = gravitational pull = 32.17 ft/sec²

t = time to achieve maximum height

Here v = 0 so

0 = 120 - (32.17)t

t = 120/32.17 = 3.73 seconds

ch4aika [34]3 years ago
4 0
Thank you for posting your question here. I hope the answer below will help. 

Vo=110 feet per second 
<span>ho=2 feet </span>
<span>So, h(t) = -16t^2 +110t +2 </span>
<span>Take the derivative: h'(t) = 110 -32t </span>
<span>The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0. </span>
<span>So, set h'(t)=0 and solve for t: </span>
<span>0 = 110 -32t </span>
<span>-110 = -32t </span>
<span>t=3.4375 </span>
<span>t=3.44 seconds </span>
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